Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to A (2v2 – 1)dx – vx dv = %3D В None of the given Choices (1+2v)dx + vx dv = 0 D (1+2v2)dx + x dv = 0 E (2v2 - 1)dx + Vx dv = 0
Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to A (2v2 – 1)dx – vx dv = %3D В None of the given Choices (1+2v)dx + vx dv = 0 D (1+2v2)dx + x dv = 0 E (2v2 - 1)dx + Vx dv = 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 44E
Related questions
Question
![Using the substitution y = vx and dy = v dx+ x dv, the
differential equation with homogeneous coefficients
(x2 + y?)dx + xy dy = 0 reduces to
A
(2v2 – 1)dx – vx dv = 0
В
None of the given Choices
(1+2v)dx + vx dv = 0
%3D
D
(1+2v2)dx + x dv = 0
E
(2v2 - 1)dx + Vx dv = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa178b9af-ae12-460a-9425-cef4cc8e8298%2F4495e468-ba72-4fc7-a9ef-af7dccdf26cb%2Fcsk1dc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using the substitution y = vx and dy = v dx+ x dv, the
differential equation with homogeneous coefficients
(x2 + y?)dx + xy dy = 0 reduces to
A
(2v2 – 1)dx – vx dv = 0
В
None of the given Choices
(1+2v)dx + vx dv = 0
%3D
D
(1+2v2)dx + x dv = 0
E
(2v2 - 1)dx + Vx dv = 0
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