Using the same charge configuration in Sample Problems 1.4 item number 2, find the resultant electric force on the charge at vertex B. Three identical point charges with charge q=+3.0×10-"C are placedat each vertex of an equilateral triangle ABC as shown. If the side of theequilateral triangle is 0.01 m, find the resultant electric force on thecharge at vertex A.2.ArGiven: q,=q, = 9c =+3.0×10-6 Cr = 0.01 mSolution:Fs on A= k=[9x10° N m²/C²|(+3.0×10""CX+3.0×10-°)](0.01 m)-9-%3D= 810 NPoint charge q, repels q.. Thus, F on A is directed to the right up at 60° (since the triangleis equilateral) with the positive x-axis. Force Fc on A is computed using the same equation.Fe on A= k|(+3.0×10 “CX+3.0×10 °C)= 19x10' N m²/C²|(0.01 m)²=810 N810 NPoint charge qc repels q,. Thus, Fcon A is directed upward tothe left at an angle of 60° with the negative x-axis.810 NTo visualize FBon A and Fc on A» Ia is placed at the origin of theCartesian coordinate system as shown. The component method isused to determine the resultant electric force F.60°60°ForceHorizontal ComponentVertical Component+810 N (cos 60°) = +405 N-810 N (cos 60°)+810 N (sin 60°) = 702 N+810 N (sin 60°) = 702 NFs on A = 810 NFcon A = 810 N-405 NResultant electric force FEF, = 0EF, = 1404 NTherefore, the resultant electric force is equal to 1404 N~1400 N acting vertically up.

Given : Charge, qA=qB=qC=+3×10-6 C Radius, r = 0.01m Determine the resultant…

Answered: Using the same charge configuration in…

Using the same charge configuration in Sample Problems 1.4 item number 2, find the resultant electric force on the charge at vertex B.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter15: Electric Forces And Fields

Section: Chapter Questions

Problem 16P: Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m,...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Using the same charge configuration in Sample Problems 1.4 item number 2, find the resultant electric force on the charge at vertex B.

Three identical point charges with charge q=+3.0×10-"C are placed
at each vertex of an equilateral triangle ABC as shown. If the side of the
equilateral triangle is 0.01 m, find the resultant electric force on the
charge at vertex A.
2.
A
r
Given: q,=q, = 9c =+3.0×10-6 C
r = 0.01 m
Solution:
Fs on A
= k
=[9x10° N m²/C²|(+3.0×10""CX+3.0×10-°)]
(0.01 m)
-9-
%3D
= 810 N
Point charge q, repels q.. Thus, F on A is directed to the right up at 60° (since the triangle
is equilateral) with the positive x-axis. Force Fc on A is computed using the same equation.
Fe on A
= k
|(+3.0×10 “CX+3.0×10 °C)
= 19x10' N m²/C²|
(0.01 m)²
=810 N
810 N
Point charge qc repels q,. Thus, Fcon A is directed upward to
the left at an angle of 60° with the negative x-axis.
810 N
To visualize FBon A and Fc on A» Ia is placed at the origin of the
Cartesian coordinate system as shown. The component method is
used to determine the resultant electric force F.
60°
60°
Force
Horizontal Component
Vertical Component
+810 N (cos 60°) = +405 N
-810 N (cos 60°)
+810 N (sin 60°) = 702 N
+810 N (sin 60°) = 702 N
Fs on A = 810 N
Fcon A = 810 N
-405 N
Resultant electric force F
EF, = 0
EF, = 1404 N
Therefore, the resultant electric force is equal to 1404 N~1400 N acting vertically up.

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