using the relationship “force equals mass times acceleration,” write an answer the following question: if an object with mass X grams is being accelerated at Z centimeters per second squared, then how much force is being exerted on the object?

using the relationship “force equals mass times acceleration,” write an answer the following question: if an object with mass X grams is being accelerated at Z centimeters per second squared, then how much force is being exerted on the object?

Related questions

Q: In the figure below, a small block is sent through point A with a speed of 9.5 m/s. Its path is…

Q: 25. A skydiver weighing 180 lb (including equipment) falls vertically downward from an altitude of…

Q: A 2.0-cm-tall object is 20 cm to the left of a lens with a focal length of 10 cm. second lens with a…

A: Height of the object, Object distance, to the left of the first lens.The focal length of the first…

Q: Apparent weight in an elevator. Suppose you are in an elevator at the top floor of a multi-story…

A: Let m be the mass of a person inside elevator Given the initial speed of elevator = 0 m/s We have…

Q: The plane carrying the supplies will be cruising at a constant velocity of 250 miles per hour…

A: The given values are,

Q: ets say we have the figure above.. help please this is our problem. a. GET THE GRAVITATIONAL FORCE…

A: Concept used: Gravitational force is directly proportional to product of masses and inversely…

Q: (2) Two masses are connected by a light string and hung over a light, frictionless pulley (meaning…

A: Such problems involving Newton's Law can be solved with the help of free body diagram. Drawing free…

Q: A ball is dropped from a tower that is 400 m tall. Assuming only gravitational force g = 9.8 m/sec2,…

A: Given data The height of the tower is h=400 m The acceleration on the ball is g=9.8 m/s2 The…

Q: LA 3 kg steel ballI falls down vertically and strikes a floor with a speed of 12 m/s. It bounces off…

A: Given data: Mass (m) = 3 kg Initial velocity (Vi) = -12 m/s Final velocity (Vf) = +12 m/s Time…

Q: A ball with mass 0.45 kg is thrown upward with initial velocity 25 m/s from the roof of a building…

A: (a) Air drag is a resistive force that always works opposite to the motion. And the work done…

Q: A box rests on the (frictionless) bed of a truck. The truck driver starts the truck and accelerates…

A: Initial frame of reference --> Acceleration of the observer is zero.Non- inertial frame of…

Q: A child runs and jumps onto a playground merry-go-round similar to the one shown. Once he lands on…

Q: An estimated force-time curve for a baseball struck by a bat is shown in the figure below. Let Fmay…

A: Fmax = 19000 N ta = 1.5 ms tb = 3 ms

Q: As a baseball is being caught, its speed goes from 31 to 0 m/s in about 0.006 s. Its mass is 0.145…

Q: Imagine a person riding in an elevator that is just leaving the top floor and picks up speed for 3…

Q: An astronaut weighing 255 Ibs on Earth is on a mission to the Moon and Mars. (a) What would he weigh…

A: (a) weight on Moon W∝gWmoonWearth=gmoongearthWmoon=gmoongearthWearth=16255 lbs4.44822 N1 lbs=189 N

Q: 6. Two carts, of mass 4.5 kg and 1.0 kg, are moving towards each other along the same straight,…

Q: 2. A cardboard box with a mass of 10.0 kg is at rest on a ramp with an angle of 25°. a. Determine…

Question

This is for my astronomy class. I don't even know where to start:

Expert Solution

Step 1

Given,

mass of the object is $m = X (g m)$

and acceleration of the object is $a = Z (c m / s^{2})$

Newton's second law:

According to Newton's second law, force is the rate of change of momentum of any object that is

$F = \frac{d p}{d t}$

Also, the change in momentum change be written as

$\begin{array}{rcl} d p & = & m (v_{f i n a l} - v_{i n i t i a l}) \\ = & m d v \end{array}$

here v_final is the final velocity and v_initial is the initial velocity of the object then, the force can be re-write as

$\begin{array}{rcl} F & = & m \frac{d v}{d t} \\ = & m a \end{array}$

So force is the product of mass and momentum.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Similar questions

Handwritten solution with free body diagram. Strictly don't use Artificial intelligence tools
Spac. Heading 1 Heading 2 Title Subtitle Paragraph Styles Name A very bored and careless person fired a bullet into the block shown. The bullet lodges into the block and the block reaches a maximum height of 2 meters. What was the initial velocity of the bullet? Don't try this at home! = 23 Bl.k Marlle
A 85 kg person stands on a scale. a.) What would be the scale readout? |N=[ mg (Express in Newtons, and as a multiple of the person's weight.) Now, find a general expression for the scale readout, in terms of the person's mass, acceleration, and/or g. Show that it can be used to get the answer for part a above, and then use it to get the answers for all of the following parts: b.) If the person stands on the scale in an elevator accelerating upwards at 1 m/s², what is the scale readout? |N=[ .mg (Does the person feel heavier or lighter than the "usual" of part a?) c.) If the person stands on the scale in an elevator accelerating downwards at 1 m/s², what is the scale readout? mg (Does the person feel heavier or lighter than usual?) d.) If the person stands on the scale in an elevator accelerating downwards at 9.8 m/s2, what is the scale readout? N= mg (Does the person feel heavier or lighter than usual?) e.) In parts b-d, was the actual weight of the person different? Explain the…
m¡m2 F = G d² 3. Effect of Varying Mass 2 Set Mass 1 to be 10 kg, the location of Mass 1 to be 0 meters, and the location of Mass 2 to be 5 meters. Complete the following table. As an example, the third column, "Ratio of force" is computed using the formula: Ratio of force = (Force when Mass 2 is 10 kg)/(Force when Mass 2 is 20 kg) %3D when Mass 2 is 20 kg. Mass 2 Force Ratio of force 01- 10 kg 1.0 10 20 kg 40 kg 100 kg 1.07x10-9 2,67x10 What do you notice about the "Ratio of forces" when the mass of Mass 2 les Die rafio SE he Doubles? e the dds2D00les Dire rafio Sahat at Triples? - O0 mema Increases by four times? What do expect the "Ratio of forces" to be when the Mass 2 is increased by 50 times?
you test various distances from a magnet to a paper clip, bro! At 20 cm apart, there is a force of 0.128 Newtons. At 40 cmapart, there is a force of 0.0320 N. At 60 cm apart, there is a force of 0.142 N. At 100cm apart, there is a force of 0.0051 NWhat is the relationship between distance and force from a magnet? Write an equation that fits this situation too.
In Lab 3 (Kinematics), you examined an object of mass m moving down a ramp tilted at an angle of 0. In that lab you were given a theoretical formula of a=g'sin(0) m a. Use forces to derive the formula above. T b. If the box is released from rest at the top of the ramp, find an expression (formula) for the speed of the box at the bottom of the ramp, vệ As part of your solution, you are required to fill out the following: FBD Forces in x-direction Forces in y-direction MacBook Pro Search or type URL % & 5 7 * 00
From inspection of the torque equation we can find another quantity called the moment of inertia, denoted I, which is the "angular mass". I = mr2 = moment of inertia This was for one point-like mass in the example, but what if we had two balls on the same string some distance apart from one another. Well like before each of these point-like masses has a torque and we are allowed to sum all our torques (similar to forces), i.e. Tnet = T1+ 72 = (mıraı + m2ržaz2)2 Then our moment of inertia for this system would be I = mır} + m2r What if we kept adding masses along the string? Well eventually we would have a distribution of masses along this string that would have to be summed for each radius squared distance they are away from our pivot. If we made a line of masses then we would need to integrate over this distribution of infinitesimal masses to find the total moment of inertia of our system, i.e. Tnet a fr² dm 2 Let's not worry too much about how one would go about integrating out a…
For the following problem please show your step by step process so your thought process can be followed. Please also show a sketch, quantities given, quantities to be found, and boxed answer with units.
Answer all questions in the space provided. Show ALL your steps in your calculations. Answer in complete sentences and therefore statement
you test various distances from a magnet to a paper clip, bro! At 20 cm apart, there is a force of 0.128 Newtons. At 40 cmapart, there is a force of 0.0320 N. At 60 cm apart, there is a force of 0.142 N. At 100cm apart, there is a force of 0.0051 NWhat is the relationship between distance and force from a magnet? Write an equation that fits this situation too.
Tony Stark is standing beside Thor who is standing on the top of Stark Tower (425 m) his hammer has a mass equal to 300 billion elephants (call it 4.5*1015 kg) Tony and Thor drop at the same time. Tony drops his lucky penny. Thor his hammer. How fast (in m/s) will Tony’s lucky penny be traveling just before it strikes the ground, assuming nothing stops it?
A 2000 -kg car skids to a halt on a wet concrete road. The car leaves skid marks that are 80 m long . (Use .25 for kinetic friction). What is the net force on the car? What was the speed of the car when the driver hit the brakes?