Using the Pythagorean theorem solve for the missing side.3.910.4O 607O 11.311

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Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter8: Applications Of Trigonometry

Section8.1: The Law Of Sines

Problem 8E

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A landscaper wants to put a square reflecting pool next to a triangular deck, as shown below. The triangular deck is a right triangle, with legs of length 9 feet and 11 feet, and the pool will be adjacent to the hypotenuse. (a) Use the Pythagorean Theorem to find the length of a side of the pool. Round your answer to the nearest tenth of a foot. (b) Find the exact area of the pool.
An artist wants to make a small monument in the shape of a square base topped by a right triangle, as shown below. The square base will be adjacent to one leg of the triangle. The other leg of the triangle will measure 2 feet and the hypotenuse will be 5 feet. (a) Use the Pythagorean Theorem to find the length of a side of the square base. Round your answer to the nearest tenth of a foot. (b) Find the exact area of the face of the square base.
A copper casting is in the shape of a prism with an equilateral triangle base. The length of each base side is 17.80 centimeters, and the casting height is 16.23 centimeters. Copper weighs 8.8 grams per cubic centimeter. Determine the weight of the casting in kilograms. One kilogram equals 1000 grams. Round the answer to 2 decimal places.
A spur gear is shown. Pitch circles of spur gears are the imaginary circles of meshing gears that make contact with each other. A pitch diameter is the diameter of a pitch circle. Circular pitch is the length of the arc measured on the pitch circle between the centers of two adjacent teeth. Determine the circular pitch of a spur gear that has 26 teeth and a pitch diameter of 4.1250 inches. Express the answer to 4 decimal places.
Find the area of this plate. All dimensions are in millimeters. Hint: The broken lines indicate one method of solution.
a. Find the distance between 35 and 23 . b. Find the distance between 35 and 23 . c. Find the distance between 35 and 23 .
A cross section of an aluminum bar in the shape of a trapezoid is shown. All the dimensions are in inches. a. Find the cross-sectional area of the bar. b. Find the length of side AB. Round the answer to the nearest hundredth inch.
Enclosing a field You have 16 miles of fence that you will use to enclose a rectangle field. a.Draw a picture to show that you can arrange the 16 miles fence into a rectangle of width 3 miles and length 5 miles. What is the area of this rectangle? b.Draw a picture to show that you can arrange the 16 miles fence into a rectangle of width 2 miles and length 6 miles. What is the area of this rectangle? c.The first two parts of this exercise are designed to show you that you can get different areas for the rectangle of the sane perimeter, 16 miles. In general, if you arrange the 16 miles of fence into a rectangle of width w miles, then it will enclose an area of A=w8-w square miles. iMake a graph of the area enclosed as a function of w, and explain what the graph is showing. iiWhat width w should you use to enclose the most area? iiiWhat is the length of the maximum-area rectangle that you made, and what kind of figure do you have?
Dr. Pepper can A Dr. Pepper aluminum can is approximately the shape of a cylinder. If the height of the can is 9 centimeters more than its radius and the volume of the can is approximately 108 cubic centimeters, find the radius of the can. The formula for the volume of a cylinder is V=r2h

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Using the Pythagorean theorem solve for the missing side. 3.9 O 10.4 O 6 07 O 11.3 11