Using the method of substitution, I = [ x²(1 + 2x³¹)³dx = [ f(u)du where u= du = f(u) = Using the above information: [ x²(1 + 2x³)³dx - f(u)du = || da (in terms (in terms
Using the method of substitution, I = [ x²(1 + 2x³¹)³dx = [ f(u)du where u= du = f(u) = Using the above information: [ x²(1 + 2x³)³dx - f(u)du = || da (in terms (in terms
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Using the method of substitution,
I
! = [ z²(1 + 2x³)³dx = [ f(u)du
where
U=
du: =
f(u) =
Using the above information:
[ x²(1 + 2x³)²dx
= [ f(u)du
=
||
dx
(in terms of u)
(in terms of x)
Note: Don't forget the constant of integration in the last two blanks.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67fa20a1-7262-4df8-92e5-c46745f93cbc%2F68b5ae10-0c64-4b7d-a2eb-773da7c55570%2Fwmmgkz_processed.png&w=3840&q=75)
Transcribed Image Text:Using the method of substitution,
I
! = [ z²(1 + 2x³)³dx = [ f(u)du
where
U=
du: =
f(u) =
Using the above information:
[ x²(1 + 2x³)²dx
= [ f(u)du
=
||
dx
(in terms of u)
(in terms of x)
Note: Don't forget the constant of integration in the last two blanks.
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Follow-up Question
These are incorrect
![u= 1+2x^3
-lu = 6x^2
f(u) = 4^2/6
Using the above information:
[ x² (1+2x³)²dx
= [ f(u)du
4^3/10 + C
(1+2x^3)^3/10 +C
dx
(in terms of u)
(in terms of x)](https://content.bartleby.com/qna-images/question/67fa20a1-7262-4df8-92e5-c46745f93cbc/e628b336-c111-43c0-b802-a381b366e9ba/horg5vl_thumbnail.png)
Transcribed Image Text:u= 1+2x^3
-lu = 6x^2
f(u) = 4^2/6
Using the above information:
[ x² (1+2x³)²dx
= [ f(u)du
4^3/10 + C
(1+2x^3)^3/10 +C
dx
(in terms of u)
(in terms of x)
Solution
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