Using the MATLAB code f=inline('x^3 - x^2 -18'); df=inline('3*x^2 - 2*x'); ea=100; count=0; xi=0.5; while (ea>.01); count = count + 13; xil = xi - f(xi)/df(xi); ea = 100*abs(xil-xi)/xi1); disp([count xi1,xi, ea]); xi=xil; end Home 1(O noPHP) I Homework 11 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 The root of the function is closest to Choices None 1 5 13 Submit I Attempts 1 1 ILLL

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### MATLAB Code for Finding Roots

The following MATLAB code utilizes Newton's method to approximate the root of the function \( f(x) = x^3 - x^2 - 18 \).

```matlab
f=inline('x^3 - x^2 -18'); 
df=inline('3*x^2 - 2*x'); 
ea=100; 
count=0; 
xi=0.5; 
while (ea>.01); 
    count = count + 1; 
    xi1 = xi - f(xi)/df(xi); 
    ea = 100*abs((xi1-xi)/xi1); 
    disp([count xi1,xi, ea]); 
    xi=xi1; 
end
```

### Explanation of Code

- **Function Definition**: The function is defined as \( f(x) = x^3 - x^2 - 18 \) and its derivative \( df(x) = 3x^2 - 2x \).
- **Initial Setup**: The approximate error (`ea`) is initialized to 100, and the initial guess (`xi`) for the root is set to 0.5. The counting variable (`count`) is initialized at 0.
- **Iteration**:
  - The loop continues until the approximate error (`ea`) is less than 0.01%.
  - Inside the loop, the next approximation of the root (`xi1`) is calculated using the formula \( x_{i+1} = x_i - \frac{f(x_i)}{df(x_i)} \).
  - The approximate error is updated and printed along with the iteration count and current approximations.
  - The value of `xi` is updated for the next iteration.

### Question

- **Root Approximation**: The root of the function is closest to one of the following choices:
  - None
  - 1
  - 5
  - 3

### Interface Elements

- **Choice Selection**: There is a table with selectable options for the root approximation.
- **Homework Navigation**: The interface contains navigation elements for different homework questions, with Q2 highlighted in a different color, indicating the current question.

Submit attempts are limited to 1.
Transcribed Image Text:### MATLAB Code for Finding Roots The following MATLAB code utilizes Newton's method to approximate the root of the function \( f(x) = x^3 - x^2 - 18 \). ```matlab f=inline('x^3 - x^2 -18'); df=inline('3*x^2 - 2*x'); ea=100; count=0; xi=0.5; while (ea>.01); count = count + 1; xi1 = xi - f(xi)/df(xi); ea = 100*abs((xi1-xi)/xi1); disp([count xi1,xi, ea]); xi=xi1; end ``` ### Explanation of Code - **Function Definition**: The function is defined as \( f(x) = x^3 - x^2 - 18 \) and its derivative \( df(x) = 3x^2 - 2x \). - **Initial Setup**: The approximate error (`ea`) is initialized to 100, and the initial guess (`xi`) for the root is set to 0.5. The counting variable (`count`) is initialized at 0. - **Iteration**: - The loop continues until the approximate error (`ea`) is less than 0.01%. - Inside the loop, the next approximation of the root (`xi1`) is calculated using the formula \( x_{i+1} = x_i - \frac{f(x_i)}{df(x_i)} \). - The approximate error is updated and printed along with the iteration count and current approximations. - The value of `xi` is updated for the next iteration. ### Question - **Root Approximation**: The root of the function is closest to one of the following choices: - None - 1 - 5 - 3 ### Interface Elements - **Choice Selection**: There is a table with selectable options for the root approximation. - **Homework Navigation**: The interface contains navigation elements for different homework questions, with Q2 highlighted in a different color, indicating the current question. Submit attempts are limited to 1.
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