Using the joint distribution describing X and Y, the following formula was derivedE(XKym) =2km+3(m+k)+4(k+1)(k+2)(m+1)(m+2)where k and m are both nonnegative constants.Simplify Var( 2X - 3Y)[ Select ]- Var(X) [Select][ Select ]Var(Y) [Select][ Select ]Cov(X,Y)

Answered: Image /qna-images/answer/d4d0c21e-b190-4244-8f43-cf234ded9bb7.jpg

Answered: Using the joint distribution describing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose we randomly draw two integers from the range [1, n] with uniform probability. Define X to be the value of the first integer drawn; define Y to be the value of the second integer drawn. Define Z = |X - Y|. Compute E(Z).
In a game, five cards are drawn out of a deck of 52 cards. If the result is a four-of-a-kind, you stop the game. Otherwise, you put the cards back into the deck and shuffle it to continue the game. Let X be the number of draws in the game. Compute E(X) and Var(X).
A box consists of 12 components, 5 of which are defective. (a) Components are selected and tested one at a time, without replacement, until a non-defective component is found. Let X be the number of tests required. Find P(X = 6). (b) Components are selected and tested, one at a time without replacement, until two consecutive non defective components are obtained. Let X be the number of tests required. Find P(X = 5).
There are 2 players in a game. Each player independently picks a real number on the interval [0, 1] uniformly. If the (absolute) difference between the two numbers is less than a (0 < a < 1) and the sum of the two numbers is less than 1, then both players win, otherwise both players lose. What is the probability of winning? 2.
An electronics store has received a shipment of 20 table radios that have connections for an iPod or iPhone. Ten of these have two slots (so they can accommodate both devices), and the other ten have a single slot. Suppose that six of the 20 radios are randomly selected to be stored under a shelf where the radios are displayed, and the remaining ones are placed in a storeroom. Let X = the number among the radios stored under the display shelf that have two slots. (a) What kind of distribution does X have (name and values of all parameters)? O hypergeometric with N = 10, M = 6, and n = 10 O binomial with n = 20, x = 10, and p = 6/20 hypergeometric with N = 20, M = 10, and n = 6 O binomial with n = 10, x = 6, and p = 6/10 (b) Compute P(X= 2), P(X ≤ 2), and P(X ≥ 2). (Round your answers to four decimal places.) P(X = 2) = P(X ≤ 2) = P(X ≥ 2) = (c) Calculate the mean value and standard deviation of X. (Round your standard deviation to two decimal places.) mean value standard deviation…
Suppose X-U (-54, 60) and F(t) is the cumulative distribution function. What is the probability that X is in the interval [-51, -21] or in the interval [-36, 57]? O (F(-21)-F(-51))+ (F(57) - F(-36)) O (F(-21)-F(-51)) x (F(57) - F(-36)) O F(-21)-F(-36) O F(57) - F(-51)
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(Use Bayes Rule) In a backyard vineyard in Napa Valley with 10 grape vines in a row, if the weather works well (just right), rain in the spring and dry through the summer, the yield for each vine is distributed roughly binomial with N=800, p=.8 . In a drought the yield is binomial with N=900 and P=.6, while if the year is too wet, the yield of useful grapes per vine is N=700, P=.85. Under climate change the probability of a just right year is about .15, of a too wet year is .15, and a dry year is .7. On a just right year the wine can sell for 200 dollars/bottle, on a dry year the quality drops so it will sell for 100 dollars a bottle, on a wet year it will sell for 25 dollars a bottls. (For a Z score with absolute value greater than 5, assume the probability is 0). a. The yield for all 10 vines was more than 6350 grapes. Given this yield: i. What is the probability that you will be able to sell for 200 dollars a bottle? (Hint: break it down, given the information, what is the…

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Using the joint distribution describing X and Y, the following formula was derived E(XKym) = 2km+3(m+k)+4 (k+1)(k+2)(m+1)(m+2) where k and m are both nonnegative constants. Simplify Var( 2X - 3Y) [ Select ] - Var(X) [Select] [ Select ] = Var(Y) [Select] [ Select [ Select ] Cov(X,Y)