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Using the given data Using Vector addition Graph the following 4 forces onto the graph below. It should be located on 1 quadrant on the graphs with all of the forces and angles combined to form a triangular shape. Label ur triangle that u have graphed. It shouldn't be in static equilibrium as there was an error in the lab experiment.

Using the given data Using Vector addition Graph the following 4 forces onto the graph below. It should be located on 1 quadrant on the graphs with all of the forces and angles combined to form a triangular shape. Label ur triangle that u have graphed. It shouldn't be in static equilibrium as there was an error in the lab experiment.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Using the given data Using Vector addition Graph the following 4 forces onto the graph below. It should be located on 1 quadrant on the graphs with all of the forces and angles combined to form a triangular shape. Label ur triangle that u have graphed. It shouldn't be in static equilibrium as there was an error in the lab experiment. 

**Static Equilibrium with Four Forces (All four angles cannot be 90 degrees)** | Force | Mass (kg) | F = 9.8 m/s² x mass (N) | Angle in degrees (θ) | \( F_x = F \cos \theta \) | \( F_y = F \sin \theta \) | |--------|-----------|-------------------------|----------------------|---------------------------|---------------------------| | Force 1 | 0.085 kg | 0.86 N | 12 | 0.81 | -0.73 | | Force 2 | 0.055 kg | 0.53 N | 67 | 0.210 | 0.17 | | Force 3 | 0.106 kg | 1.03 N | 175 | -1.035 | 0.50 | | Force 4 | 0.075 kg | 0.73 N | 275 | 0.06 | 0.09 | **Sum of x component and y component of each force:** - \( \sum F_x = 0.04 \) - \( \sum F_y = 0.03 \) **Explanation of the Graph** The graph is a grid layout suitable for plotting the components of the forces listed in the table. The x-axis and y-axis are centered in the middle of the grid, allowing for both positive and negative values, which is essential for accurately representing forces with both positive and negative components. Each square on the grid can be used to represent specific units of the force components, typically in Newtons, based on the scale chosen by the user. This visual representation helps in understanding how the individual components sum up to achieve static equilibrium.
Transcribed Image Text:**Static Equilibrium with Four Forces (All four angles cannot be 90 degrees)** | Force | Mass (kg) | F = 9.8 m/s² x mass (N) | Angle in degrees (θ) | \( F_x = F \cos \theta \) | \( F_y = F \sin \theta \) | |--------|-----------|-------------------------|----------------------|---------------------------|---------------------------| | Force 1 | 0.085 kg | 0.86 N | 12 | 0.81 | -0.73 | | Force 2 | 0.055 kg | 0.53 N | 67 | 0.210 | 0.17 | | Force 3 | 0.106 kg | 1.03 N | 175 | -1.035 | 0.50 | | Force 4 | 0.075 kg | 0.73 N | 275 | 0.06 | 0.09 | **Sum of x component and y component of each force:** - \( \sum F_x = 0.04 \) - \( \sum F_y = 0.03 \) **Explanation of the Graph** The graph is a grid layout suitable for plotting the components of the forces listed in the table. The x-axis and y-axis are centered in the middle of the grid, allowing for both positive and negative values, which is essential for accurately representing forces with both positive and negative components. Each square on the grid can be used to represent specific units of the force components, typically in Newtons, based on the scale chosen by the user. This visual representation helps in understanding how the individual components sum up to achieve static equilibrium.
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