Using the following code of the Simplified Bresenham algorithm, show the complete steps for drawing a line from the point (1, -3) to the point (-4, 0) in a 2D Cartesian domain. function line(x0, y0, x1, y1) dx := abs(x1-x0) dy := abs(y1-y0) if x0 < x1 then sx := 1 else sx := -1 if y0 < y1 then sy := 1 else sy := -1 err := dx-dy loop plot(x0,y0) if x0 = x1 and y0 = y1 exit loop e2 := 2*err if e2 > -dy then err := err - dy x0 := x0 + sx end if if x0 = x1 and y0 = y1 then plot(x0,y0) exit loop end if if e2 < dx then err := err + dx y0 := y0 + sy end if end loop
Using the following code of the Simplified Bresenham algorithm, show the complete steps for drawing a line from the point (1, -3) to the point (-4, 0) in a 2D Cartesian domain. function line(x0, y0, x1, y1) dx := abs(x1-x0) dy := abs(y1-y0) if x0 < x1 then sx := 1 else sx := -1 if y0 < y1 then sy := 1 else sy := -1 err := dx-dy loop plot(x0,y0) if x0 = x1 and y0 = y1 exit loop e2 := 2*err if e2 > -dy then err := err - dy x0 := x0 + sx end if if x0 = x1 and y0 = y1 then plot(x0,y0) exit loop end if if e2 < dx then err := err + dx y0 := y0 + sy end if end loop
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Using the following code of the Simplified Bresenham
function line(x0, y0, x1, y1)
dx := abs(x1-x0)
dy := abs(y1-y0)
if x0 < x1 then sx := 1 else sx := -1
if y0 < y1 then sy := 1 else sy := -1
err := dx-dy
loop
plot(x0,y0)
if x0 = x1 and y0 = y1 exit loop
e2 := 2*err
if e2 > -dy then
err := err - dy
x0 := x0 + sx
end if
if x0 = x1 and y0 = y1 then
plot(x0,y0)
exit loop
end if
if e2 < dx then
err := err + dx
y0 := y0 + sy
end if
end loop
![3
1
4.01
-5 -4
1
4 5
-6
-3
-2
-1
3
-2
-3
1,31
-4
-5
-6
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbde4e6fc-5256-4490-bdd8-a99ebceec0dd%2F15977ace-a534-44fb-aa22-d1bcff7c333f%2Funzw86t_processed.png&w=3840&q=75)
Transcribed Image Text:3
1
4.01
-5 -4
1
4 5
-6
-3
-2
-1
3
-2
-3
1,31
-4
-5
-6
2.
![Using the following code of the Simplified Bresenham algorithm, show the
complete steps for drawing a line from the point (1, -3) to the point (-4, 0) in a 2D
Cartesian domain.
function line (x0, yo, xl, yl)
dx :- abs (xl-x0)
dy := abs (yl-y0)
if x0 < xl then sx := 1 else sx := -1
SX
if yo < yl then sy := 1 else sy := -1
:= dx-dy
err
loop
plot (x0, y0)
if x0 = xl and yo =
yl exit loop
e2 := 2*err
if e2 > -dy then
err := err
dy
x0 := x0 + Sx
end if
if x0 = xl and yo = yl then
plot (x0, y0)
exit loop
end if
if e2 <
dx then
err := err + dx
yo := yo + sy
end if
end loop](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbde4e6fc-5256-4490-bdd8-a99ebceec0dd%2F15977ace-a534-44fb-aa22-d1bcff7c333f%2Fphodq4g_processed.png&w=3840&q=75)
Transcribed Image Text:Using the following code of the Simplified Bresenham algorithm, show the
complete steps for drawing a line from the point (1, -3) to the point (-4, 0) in a 2D
Cartesian domain.
function line (x0, yo, xl, yl)
dx :- abs (xl-x0)
dy := abs (yl-y0)
if x0 < xl then sx := 1 else sx := -1
SX
if yo < yl then sy := 1 else sy := -1
:= dx-dy
err
loop
plot (x0, y0)
if x0 = xl and yo =
yl exit loop
e2 := 2*err
if e2 > -dy then
err := err
dy
x0 := x0 + Sx
end if
if x0 = xl and yo = yl then
plot (x0, y0)
exit loop
end if
if e2 <
dx then
err := err + dx
yo := yo + sy
end if
end loop
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