Using the equations 2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.6 kJ/mol C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/mol   Determine the molar enthalpy (in kJ/mol) for the reaction 6 C (s) + 3 H₂ (g) → C₆H₆ (l).

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Using the equations

2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6 H₂O (g)∆H° = -6271 kJ/mol

2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.6 kJ/mol

C (s) + O₂ (g) → CO₂ (g) ∆H° = -393.5 kJ/mol

 

Determine the molar enthalpy (in kJ/mol) for the reaction

6 C (s) + 3 H₂ (g) → C₆H₆ (l).

The image depicts chemical reactions along with their enthalpy changes (ΔH) written on graph paper. Here is the transcription and explanation:

1. Reaction 1:
   - **Chemical Equation:** 
     \[
     6\text{C(s)} + 3\text{H}_2\text{(g)} \rightarrow \text{C}_6\text{H}_6
     \]
   - **ΔH:** Moved and combined in the equations below.

2. Reaction 2:
   - **Chemical Equation:**
     \[
     \frac{3}{2} (\text{C}_6\text{H}_6\text{(l)}) + \frac{15}{2}\text{O}_2\text{(g)} \rightarrow 15\text{O}_2\text{(g)} + 2\text{C}_6\text{H}_6\text{(l)}
     \]
   - **ΔH:** \(\text{ΔH: } 6271 = 3133.5\)

3. Reaction 3:
   - **Chemical Equation:**
     \[
     (\cancel{\text{C}_6\text{H}_6\text{(l)}}) + \cancel{\frac{15}{2}\text{O}_2\text{(g)}} \rightarrow \cancel{\frac{21}{2}}\text{O}_2
     \]
   - This section is largely struck through.

4. Reaction 4:
   - **Chemical Equation:**
     \[
     6\text{C(s)} + 3\text{O}_2\text{(g)} \rightarrow 6\text{CO}_2\text{(g)}
     \]
   - **ΔH:** \(\text{ΔH: } -393.5 \times 6 = -2361\)

5. Reaction 5:
   - **Chemical Equation:**
     \[
     3\text{H}_2\text{O(l)} + 6\text{O}_2\text{(g)} \rightarrow \cancel{12\text{CO}_2\text{(g)}} - \text{C}_6\text{H}_6\text{(l)}
     \]
   - **ΔH:** \(\text{Δ
Transcribed Image Text:The image depicts chemical reactions along with their enthalpy changes (ΔH) written on graph paper. Here is the transcription and explanation: 1. Reaction 1: - **Chemical Equation:** \[ 6\text{C(s)} + 3\text{H}_2\text{(g)} \rightarrow \text{C}_6\text{H}_6 \] - **ΔH:** Moved and combined in the equations below. 2. Reaction 2: - **Chemical Equation:** \[ \frac{3}{2} (\text{C}_6\text{H}_6\text{(l)}) + \frac{15}{2}\text{O}_2\text{(g)} \rightarrow 15\text{O}_2\text{(g)} + 2\text{C}_6\text{H}_6\text{(l)} \] - **ΔH:** \(\text{ΔH: } 6271 = 3133.5\) 3. Reaction 3: - **Chemical Equation:** \[ (\cancel{\text{C}_6\text{H}_6\text{(l)}}) + \cancel{\frac{15}{2}\text{O}_2\text{(g)}} \rightarrow \cancel{\frac{21}{2}}\text{O}_2 \] - This section is largely struck through. 4. Reaction 4: - **Chemical Equation:** \[ 6\text{C(s)} + 3\text{O}_2\text{(g)} \rightarrow 6\text{CO}_2\text{(g)} \] - **ΔH:** \(\text{ΔH: } -393.5 \times 6 = -2361\) 5. Reaction 5: - **Chemical Equation:** \[ 3\text{H}_2\text{O(l)} + 6\text{O}_2\text{(g)} \rightarrow \cancel{12\text{CO}_2\text{(g)}} - \text{C}_6\text{H}_6\text{(l)} \] - **ΔH:** \(\text{Δ
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