Using the data in the table, determine the rate constant of Trial [A] (M) [B] (M) Rate (M/s) the reaction and select the appropriate units. 1 0.300 0.400 0.0112 2 0.300 0.800 0.0112 A + 2B C+D 3 0.600 0.400 0.0448 Units k =
Using the data in the table, determine the rate constant of Trial [A] (M) [B] (M) Rate (M/s) the reaction and select the appropriate units. 1 0.300 0.400 0.0112 2 0.300 0.800 0.0112 A + 2B C+D 3 0.600 0.400 0.0448 Units k =
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the data in the table, determine the rate constant of
Trial [A] (M) [B] (M) Rate (M/s)
the reaction and select the appropriate units.
1
0.300
0.400
0.0112
2
0.300
0.800
0.0112
A + 2B C+D
3
0.600
0.400
0.0448
Units
k =||
%D
TOOLS
M-'s-1
x10
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Transcribed Image Text:Attem
Using the data in the table, determine the rate constant of
Trial [A] (M) [B] (M) Rate (M/s)
the reaction and select the appropriate units.
1
0.300
0.400
0.0112
2
0.300
0.800
0.0112
A + 2B C+D
3
0.600
0.400
0.0448
Units
k =||
%D
TOOLS
M-'s-1
x10
|help
terms of use
contact us
careers
privacy policy
about us
prime
video
W
Expert Solution
Introduction
The rate law for this reaction is,
rate = k [A]x [B]y
substitute given value from the table to find the rate constant.
0.0112 = k [0.300]x [0.400]y ------- (1)
0.0112 = k [0.300]x[0.800]y ------- (2)
0.0448 = k [0.600]x[0.400]y ------- (3)
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