Using the commutation relation for spin, namely that [Sx, Sy] = iSz (and cyclic permutations), prove that [Ŝ . X, Ŝ) = iŝ x X, (1.75) where X is a vector.
Using the commutation relation for spin, namely that [Sx, Sy] = iSz (and cyclic permutations), prove that [Ŝ . X, Ŝ) = iŝ x X, (1.75) where X is a vector.
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Using the commutation relation for spin, namely that [Sx,Sy]=iSz (and cyclic premutations), prove that [S.X , S]=iS×X , where X is a vector.
![Using the commutation relation for spin, namely that
[Sx, Sy] = iSz (and cyclic permutations), prove that
[Ŝ - X, Ŝ) = iŝ x X,
(1.75)
where X is a vector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F28ab2631-7813-469a-bbbe-54b8c978492b%2F107ed8bc-0c67-4af8-b029-315998e35737%2Fishg46v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using the commutation relation for spin, namely that
[Sx, Sy] = iSz (and cyclic permutations), prove that
[Ŝ - X, Ŝ) = iŝ x X,
(1.75)
where X is a vector.
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