The accompanying frequency distribution summarizessample data consisting of ages of randomly selectedinmates in federal prisons. Use the data to construct a99% confidence interval estimate of the mean age of allinmates in federal prisons.Age (years)Number16–251326–356036-456646-553656-6515Over 654Using the class limits of 66–75 for the "over 65" group, find the confidence interval.

Given: Age Number 16-25 13 26-35 60 36-45 66 46-55 36 56-65 15 66-75 4

Answered: Using the class limits of 66–75 for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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data consist of height measurements in centimeters of 5 randomly selected children at ages 3 and 5. Assume data are observed from 2 independent normal populations. find a 95% confidence interval of the form (a,b) with -inf < a < b < +inf for the difference in height among children between ages 3 and 5
Express the confidence interval 68.8%<p<84% in the form of p±ME.___% ± ___%
6.2.9-T Construct the indicated confidence interval for the population mean u using the t-distribution. Assume the population is normally distributed. c = 0.99, x= 13.8, s=4.0, n= 10 The 99% confidence interval using a t-distribution is ( D (Round to one decimal place as needed.)
n a random sample of 375 students at a university, 315 stated that they were nonsmokers. Based on this sample, compute a 95% confidence interval for the proportion of all students at the university who are nonsmokers. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
A psychologist is interested in the mean IQ score of a given group of children. It is known that the IQ scores of the group have a standard deviation of 13. The psychologist randomly selects 100 children from this group and finds that their mean IQ score is 111. Based on this sample, find a 95% confidence interval for the true mean IQ score for all children of this group. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: 5? Upper limit:
Construct a 99% confidence interval to estimate the population mean using the data below. x-51 0 =9 n= 43 With 99% confidence, when n= 43 the population mean is between a lower limit of and an upper limit of (Round to two decimal places as needed.) Enter your answer in each of the answer boxes. Save for Later. O Type here to search .::: ace F9 F1C F7 F8 F5 F6 F2 F3 F4 出
Express the confidence interval (29.2%,37%) in the form of ˆp±MEp.___% ± ___%
A psychologist is interested in the mean IQ score of a given group of children. It is known that the IQ scores of the group have a standard deviation of 14. The psychologist randomly selects 80 children from this group and finds that their mean IQ score is 111. Based on this sample, find a 99% confidence interval for the true mean IQ score for all children of this group. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
Express the confidence interval (0.025,0.079) in the form of p-E
When do creative people get their good ideas? USA Today did a survey of 966 inventors (who hold U.S. patents) and obtained the following information. Assuming that the time interval includes the left limit and all the times up to but not including the right limit, the probability that an inventor has a good idea during each time interval is the following: P(6 A.M.-noon) = 290/966, P(noon-6 P.M.) = 135/966, P(6 P.M.-midnight) = 319/966, P(midnight-6 A.M) = 222/966. State whether the following statement is true or false.All the outcomes are not equally likely.

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Using the class limits of 66–75 for the "over 65" group, find the confidence interval. |<µ< (Round to one decimal place as needed.)