Using the binomial coefficients (2) = n n! (n-k)!k! (1) The sum first n integers: 1 + 2 + ... + n = prove that the following is correct: = 2n k=0 Use part 1 to argue that given a set A = {a₁,..., an} with n objects, that the number of subsets of A, that is the number of sets in P(A), is 2". You may find the following helpful, but I do not guarantee that you will need all of these. The sum of a geometric series 1 + r + r² + ... + pn = n(n+1) 2 The sum of first n squared integers: 1² + 2² + ... pn+1-1 r-1 ·+n². n(n+1)(2n+1)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Using the binomial coefficients (2)
n!
(n-k)!k!
n
Σ(3)
k=0
The sum first n integers: 1 +2 + ... + n =
prove that the following is correct:
= : 2n
Use part 1 to argue that given a set A = {a₁, an} with n objects, that the number of
subsets of A, that is the number of sets in P(A), is 2".
You may find the following helpful, but I do not guarantee that you will need all of these.
The sum of a geometric series 1+r+r² + + rn =
n(n+1)
2
pn+1_1
r-1
The sum of first n squared integers: 1² + 2² + ... + n² =
n(n+1)(2n+1)
6
Transcribed Image Text:Using the binomial coefficients (2) n! (n-k)!k! n Σ(3) k=0 The sum first n integers: 1 +2 + ... + n = prove that the following is correct: = : 2n Use part 1 to argue that given a set A = {a₁, an} with n objects, that the number of subsets of A, that is the number of sets in P(A), is 2". You may find the following helpful, but I do not guarantee that you will need all of these. The sum of a geometric series 1+r+r² + + rn = n(n+1) 2 pn+1_1 r-1 The sum of first n squared integers: 1² + 2² + ... + n² = n(n+1)(2n+1) 6
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