Using the approximated formula for the period of the oscillation, and the measures of period (T) found in Table 1, estimate the value of g for each initial angle. Assuming a value of g equal to 9.81 m/s 2, calculate the relative error for each initial angle. Record your results in Table 1.a. formula: t=2pi sqrt l/g
|
Length of string: 100 cm |
Table 1-Effect of oscillation amplitude |
|
The bob’s Time to complete 5 cycles |
|
|
|
Mass of bob: 0.025 grams |
|
Initial bob angle: (degrees) |
Horizontal amplitude displacement |
Trial 1 -Sec |
Trail 2 -Sec |
Trial 3 -Sec |
Avg. 5 cycles. |
Std. Dev. 5 cycles |
Estimated period 1 cycle. |
|
5 deg |
32 cm |
10 |
9.5 |
10 |
9.83 |
,288 |
2.1 |
|
10 deg |
52 cm |
9.5 |
9.8 |
9.9 |
9.73 |
.208 |
1.9 |
|
15 deg |
59 cm |
9.9 |
10 |
9.7 |
9.866 |
.152 |
1.98 |
|
20 deg |
70 cm |
9.9 |
10 |
9.8 |
9.9 |
.1 |
1.98 |
|
25 deg |
84 cm |
9.9 |
10 |
9.9 |
9.933 |
.057 |
1.98 |
|
30 deg |
97 cm |
9.7 |
10.1 |
10 |
9.933 |
.208 |
1,94 |
Using the approximated formula for the period of the oscillation, and the measures of period (T) found in Table 1, estimate the value of g for each initial angle. Assuming a value of g equal to 9.81 m/s 2, calculate the relative error for each initial angle. Record your results in Table 1.a.
formula: t=2pi sqrt l/g
|
Initial Angle - degrees |
Estimated value of g |
% error |
|
5 |
|
|
|
10 |
|
|
|
15 |
|
|
|
20 |
|
|
|
25 |
|
|
|
30 |
|
|
(Im not sure what time value I am suppose to use to calculate the values for the chart above)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
