Using the AH values below for equations (7), (8) and (9), calculate an experimental AH for equation (10). Hint: use Hess's law. Note: NOT the values the experiment provides, so do not try to enter these on the Data Sheet. equation (7) Mg(s) + ½ 02(g) → MgO(s) AH = -602 kJ equation (8) MgO(s) +2HCI(aq) → MgCl2(aq) +H2O(1) AH = -136 kJ equation (9) Mg(s) + 2HCI(aq) → MgCl2(aq) + H2(g) AH = -452 kJ equation (10) H2(g) + ½ 02(g) → H2O(1) AH = ??? kJ
Using the AH values below for equations (7), (8) and (9), calculate an experimental AH for equation (10). Hint: use Hess's law. Note: NOT the values the experiment provides, so do not try to enter these on the Data Sheet. equation (7) Mg(s) + ½ 02(g) → MgO(s) AH = -602 kJ equation (8) MgO(s) +2HCI(aq) → MgCl2(aq) +H2O(1) AH = -136 kJ equation (9) Mg(s) + 2HCI(aq) → MgCl2(aq) + H2(g) AH = -452 kJ equation (10) H2(g) + ½ 02(g) → H2O(1) AH = ??? kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Using the AH values below for equations (7), (8) and (9), calculate an experimental AH for equation (10). Hint: use Hess's law. Note: These are
NOT the values the experiment provides, so do not try to enter these on the Data Sheet.
equation (7) Mg(s) + ½ 02(g) → MgO(s)
AH = -602 kJ
equation (8) MgO(s) +2HCI(aq) → MgCl2(aq) +H2O(1)
AH = -136 kJ
equation (9) Mg(s) + 2HCI(aq) → MgCl2(aq) + H2(g)
AH = -452 kJ
equation (10) H2(g) + ½ 02(g) → H2O(1)
AH = ??? kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa563c0cc-a924-4c37-9f6b-c4caff62891a%2Fef2c0348-01c1-438b-b36d-5ac20ac172a0%2Ffuse0ml_processed.png&w=3840&q=75)
Transcribed Image Text:Using the AH values below for equations (7), (8) and (9), calculate an experimental AH for equation (10). Hint: use Hess's law. Note: These are
NOT the values the experiment provides, so do not try to enter these on the Data Sheet.
equation (7) Mg(s) + ½ 02(g) → MgO(s)
AH = -602 kJ
equation (8) MgO(s) +2HCI(aq) → MgCl2(aq) +H2O(1)
AH = -136 kJ
equation (9) Mg(s) + 2HCI(aq) → MgCl2(aq) + H2(g)
AH = -452 kJ
equation (10) H2(g) + ½ 02(g) → H2O(1)
AH = ??? kJ
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