Using Superposition to determine V_{1} and V_{2} 0.21x 5 ΚΩ 1V DV_{1}=-0,2373 V; V_{2}=-0,2373 V V_{1} =-2372.68 V; V_{2}=-2372.75 V DV_{1}=2372.68 V; V_{2}=2372.75 V DV_{1}=0.2373 V: V_{2}=0,2373 V *7 ΚΩ V 2 ΚΩ (1) 2 A
Using Superposition to determine V_{1} and V_{2} 0.21x 5 ΚΩ 1V DV_{1}=-0,2373 V; V_{2}=-0,2373 V V_{1} =-2372.68 V; V_{2}=-2372.75 V DV_{1}=2372.68 V; V_{2}=2372.75 V DV_{1}=0.2373 V: V_{2}=0,2373 V *7 ΚΩ V 2 ΚΩ (1) 2 A
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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USING SUPERPOSITION TO DETERMINE V _(1) AND V _(2)(NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE)

Transcribed Image Text:Using Superposition to determine V_{1} and V_{2}
0.21x
5 ΚΩ
1V
DV_{1}=-0,2373 V; V_{2}=-0,2373 V
V_{1} =-2372.68 V; V_{2}=-2372.75 V
DV_{1}=2372.68 V; V_{2}=2372.75 V
DV_{1}=0.2373 V: V_{2}=0,2373 V
*7 ΚΩ
V
2 ΚΩ
(1) 2 A
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