Using superposition, determine the current through the inductance XL for the network below I = 0.3 AZ 60° L'with E shorted IL"with I opened IL = 11 2 XL ell H₁₁ IL 8 Ω 2 7 Xc50 + E 10 V 0° units units units
Using superposition, determine the current through the inductance XL for the network below I = 0.3 AZ 60° L'with E shorted IL"with I opened IL = 11 2 XL ell H₁₁ IL 8 Ω 2 7 Xc50 + E 10 V 0° units units units
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
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Chapter7: Alternating Current, Power Distribution, And Voltage Systems
Section: Chapter Questions
Problem 7RQ
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![Using superposition, determine the current through the inductance XL for the network below
I 0.3 AZ 60°
=
L'with E shorted
L"with I opened
IL:
=
=
V
XL
|I₁
moo
IL
8 Ω
2
V
Xc
5Ω
+
E = 10 V Z 0°
units
units
units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad9295fc-5481-4a7f-a168-320e8bdc5958%2F363a20bc-ce86-4ada-9473-32865609472f%2F6px9kc_processed.png&w=3840&q=75)
Transcribed Image Text:Using superposition, determine the current through the inductance XL for the network below
I 0.3 AZ 60°
=
L'with E shorted
L"with I opened
IL:
=
=
V
XL
|I₁
moo
IL
8 Ω
2
V
Xc
5Ω
+
E = 10 V Z 0°
units
units
units
![Using superposition, determine the current through the inductance XL for the network below
E₁ = 30 V/30°
I'with
with E2 shorted
I"with E1 shorted
IL
=
R 3 Ω
V
XL
ell
2
2
8 Ω
Xc60
+
E₂ = 60 V/10°
units
units
units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad9295fc-5481-4a7f-a168-320e8bdc5958%2F363a20bc-ce86-4ada-9473-32865609472f%2F6eifwl_processed.png&w=3840&q=75)
Transcribed Image Text:Using superposition, determine the current through the inductance XL for the network below
E₁ = 30 V/30°
I'with
with E2 shorted
I"with E1 shorted
IL
=
R 3 Ω
V
XL
ell
2
2
8 Ω
Xc60
+
E₂ = 60 V/10°
units
units
units
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