Using power series methods, the solution of 2xy" + y + 2y = 0 is Oy=ω Σ (-2)" z" n!1-3-5---(2n-1) (-2)" z" +gri En=1 n|3:5-7.-- (2n+1)| (-2)" z" O y = co En=1 n1.3-5--(2n-1)| (-2)" z" n=1 n!3-5-7---(2n+1)] . Co. (-2)" z Oy = co 1+Ln=1 nl1:35-(2n-1)| +ci [1+Zn=1 (-2)" z" n!3-5-7---(2n+1) Oy =co [1+E [1+E (-2)" z" (-2)" z n=1 n!3-5-7.--(2n+1)]. n![1-3-5-(2n-1)1.
Using power series methods, the solution of 2xy" + y + 2y = 0 is Oy=ω Σ (-2)" z" n!1-3-5---(2n-1) (-2)" z" +gri En=1 n|3:5-7.-- (2n+1)| (-2)" z" O y = co En=1 n1.3-5--(2n-1)| (-2)" z" n=1 n!3-5-7---(2n+1)] . Co. (-2)" z Oy = co 1+Ln=1 nl1:35-(2n-1)| +ci [1+Zn=1 (-2)" z" n!3-5-7---(2n+1) Oy =co [1+E [1+E (-2)" z" (-2)" z n=1 n!3-5-7.--(2n+1)]. n![1-3-5-(2n-1)1.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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5) Please help with following multiple choice ASAP!
![Using power series methods, the solution of 2xy" + y + 2y = 0 is
(-2)" "
Oy3 Con-1 께13:5 (2n-1)|
(-2)" "
+ Cie n-1 피3:5-7 (2n+1)|
O y = co En=1
(-2)" a"
n![1-3-5. (2n-1)]
(-2)" z"
+ C122 |1+ n=1 끼3-5-7 (2n+1)]
(-2)" z
+ Ci
O y = co 1+En=1 nl135-(2n-1).
n![1-3-5(2n-1)].
(-2)" z"
n![3-5-7.(2n+1)]
+Σ1
(-2)" z"
Oy = co 1+n=1 n1.3-5- (2n-1)+cr 1+En-1
(-2)" z"
=1 n![3-5-7(2n+1)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74a43f44-8ce4-41e9-89f6-5a77f02dff59%2F10d8c130-ad7e-4a71-9e24-a64321936a66%2Ffsks41ow_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Using power series methods, the solution of 2xy" + y + 2y = 0 is
(-2)" "
Oy3 Con-1 께13:5 (2n-1)|
(-2)" "
+ Cie n-1 피3:5-7 (2n+1)|
O y = co En=1
(-2)" a"
n![1-3-5. (2n-1)]
(-2)" z"
+ C122 |1+ n=1 끼3-5-7 (2n+1)]
(-2)" z
+ Ci
O y = co 1+En=1 nl135-(2n-1).
n![1-3-5(2n-1)].
(-2)" z"
n![3-5-7.(2n+1)]
+Σ1
(-2)" z"
Oy = co 1+n=1 n1.3-5- (2n-1)+cr 1+En-1
(-2)" z"
=1 n![3-5-7(2n+1)]
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