Using only the Laplace transform table (Figure 11.5) in the Glyn James textbook, obtain the Laplace transform of the following function: f(t) = sinh(5t)+cos(2t),

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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Laplace transform, substitute for sinh is given. Please provide answer in a single fraction

(a) f(t)
(b)
C₂
t
ekt
ca constant
na positive integer
k a constant
sin at,
cos at,
a a real constant
a a real constant
esin at, k and a real constants
e-*t cos at,
k and a real constants
L{f(t)} = F(s)
C
L{tf(t)} = (-1)"-
S
- = -
dºF(s)
ds"
s- k
a
s² + a²
S
² + a²
a
(s + k)² + a²
s+k
(s + k)² + a²
Linearity:
First shift theorem: L{ef(t)} = F(sa),
Derivative of transform:
Region of convergence
Re(s) > 0
Re(s) > 0
Re(s) > 0
Re(s) > Re(K)
Re(s) > 0
Re(s) > 0
L{f(t)} = F(s), Re(s) > 0₁ and L{g(t)} = G(s), Re(s) > 0₂
L{af(t) + ßg(t)} = aF(s) + BG(s), Re(s) > max(₁, ₂)
Re(s) > ₁ + Re(a)
Re(s) > -k
Re(s) > -k
(n= 1, 2, ...), Re(s) > 0₁
Transcribed Image Text:(a) f(t) (b) C₂ t ekt ca constant na positive integer k a constant sin at, cos at, a a real constant a a real constant esin at, k and a real constants e-*t cos at, k and a real constants L{f(t)} = F(s) C L{tf(t)} = (-1)"- S - = - dºF(s) ds" s- k a s² + a² S ² + a² a (s + k)² + a² s+k (s + k)² + a² Linearity: First shift theorem: L{ef(t)} = F(sa), Derivative of transform: Region of convergence Re(s) > 0 Re(s) > 0 Re(s) > 0 Re(s) > Re(K) Re(s) > 0 Re(s) > 0 L{f(t)} = F(s), Re(s) > 0₁ and L{g(t)} = G(s), Re(s) > 0₂ L{af(t) + ßg(t)} = aF(s) + BG(s), Re(s) > max(₁, ₂) Re(s) > ₁ + Re(a) Re(s) > -k Re(s) > -k (n= 1, 2, ...), Re(s) > 0₁
Using only the Laplace transform table (Figure 11.5) in the Glyn James
textbook, obtain the Laplace transform of the following function:
f(t) = sinh(5t) + cos(2t),
where "sinh" stands for hyperbolic sine and sinh(x) = -₂.
Transcribed Image Text:Using only the Laplace transform table (Figure 11.5) in the Glyn James textbook, obtain the Laplace transform of the following function: f(t) = sinh(5t) + cos(2t), where "sinh" stands for hyperbolic sine and sinh(x) = -₂.
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