Using Newton's Divided Difference, the interpolating polynomial of the points (xo.Yo) = (- 2,1), (x1,V1) = (- 1,3) , (x2.y2) = (0,2), (x3,Y3) = (1, – 2), and (x4.Y4) = (2,– 1), p(x) = co + C1P1(x)+ c2P2(x) + C3P3(x) + C4Pa(x). Now, compute P(3). can be represented by A 17.8 В 22.3 20.6 15.4
Using Newton's Divided Difference, the interpolating polynomial of the points (xo.Yo) = (- 2,1), (x1,V1) = (- 1,3) , (x2.y2) = (0,2), (x3,Y3) = (1, – 2), and (x4.Y4) = (2,– 1), p(x) = co + C1P1(x)+ c2P2(x) + C3P3(x) + C4Pa(x). Now, compute P(3). can be represented by A 17.8 В 22.3 20.6 15.4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Using Newton's Divided Difference, the interpolating polynomial of the points
(xo,Yo) = (- 2,1),(x1,yı)=(-1,3), (x2,y2) = (0,2) , (x3,Y3) = (1, – 2) , and (x4,Y4) = (2, – 1) can be represented by
p(x) = co + C1P1(x)+ c2P2(x)+ C3P3(x) + C4P4(x) . Now, compute P(3).
A
17.8
22.3
c) 20.6
15.4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffea61e95-578c-44b9-9524-6154f40dcf29%2Fe8a18b61-904b-4502-b37d-b98b1df3dd9f%2Fo7y26j3_processed.png&w=3840&q=75)
Transcribed Image Text:Using Newton's Divided Difference, the interpolating polynomial of the points
(xo,Yo) = (- 2,1),(x1,yı)=(-1,3), (x2,y2) = (0,2) , (x3,Y3) = (1, – 2) , and (x4,Y4) = (2, – 1) can be represented by
p(x) = co + C1P1(x)+ c2P2(x)+ C3P3(x) + C4P4(x) . Now, compute P(3).
A
17.8
22.3
c) 20.6
15.4
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