W = 1317 kN/m Using Moment Distribution Method, determine all reactions at supports also, determine shear andbending moments with complete labels. Use I = 1/12 bh^3 and E = 2.15x10^7 KPa. Use eight(8)I.iterations.II.Using Slope Deflection Method, determine all reactions at supports also, determine shear andbending moments with complete labels. Use I= 1/12 bh^3 and E = 2.15x10^7 KPaII.Using Three Moment Equation, determine all reactions at supports also, determine shear andbending moments with complete labels. Use I= 1/12 bh^3 and E = 2.15x10^7 KPa"Wx(1m)" KN"W" KN/m"Wx1/2" KN/mBD1.0 m2.0 m5.0 m5.0 mb = 0.30mh = 0.40m5.0 mb = 0.35mh = 0.45mb = 0.40mh = 0.50mII"Wx(1m)" KN"W" KN/m"Wx1/2" KN/mBD3.0 m 1.0 m6.0 m3.0 mb = 0.50m3.0 mb = 0.45mh = 0.55mb = 0.55mh = 0.60mh = 0.65mII"Wx(1m)" KN"W" KN/m"Wx1/2" KN/mD4.0 m3.0 m7.0 m4.0 mb = 0.35mh = 0.70m4.0 mb = 0.25mb = 0.45mh = 0.50mh = 0.90mC.

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Answered: Using Moment Distribution Method,…

Using Moment Distribution Method, determine all reactions at supports also, determine shear and bending moments with complete labels. Use I = 1/12 bh^3 and E = 2.15x10^7 KPa. Use eight(8) I.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

W = 1317 kN/m

Using Moment Distribution Method, determine all reactions at supports also, determine shear and
bending moments with complete labels. Use I = 1/12 bh^3 and E = 2.15x10^7 KPa. Use eight(8)
I.
iterations.
II.
Using Slope Deflection Method, determine all reactions at supports also, determine shear and
bending moments with complete labels. Use I= 1/12 bh^3 and E = 2.15x10^7 KPa
II.
Using Three Moment Equation, determine all reactions at supports also, determine shear and
bending moments with complete labels. Use I= 1/12 bh^3 and E = 2.15x10^7 KPa
"Wx(1m)" KN
"W" KN/m
"Wx1/2" KN/m
B
D
1.0 m
2.0 m
5.0 m
5.0 m
b = 0.30m
h = 0.40m
5.0 m
b = 0.35m
h = 0.45m
b = 0.40m
h = 0.50m
II
"Wx(1m)" KN
"W" KN/m
"Wx1/2" KN/m
B
D
3.0 m 1.0 m
6.0 m
3.0 m
b = 0.50m
3.0 m
b = 0.45m
h = 0.55m
b = 0.55m
h = 0.60m
h = 0.65m
II
"Wx(1m)" KN
"W" KN/m
"Wx1/2" KN/m
D
4.0 m
3.0 m
7.0 m
4.0 m
b = 0.35m
h = 0.70m
4.0 m
b = 0.25m
b = 0.45m
h = 0.50m
h = 0.90m
C.

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