Using mesh currents analysis technique finds the current i and i2 of the circuit described in fig. 3. 0.1 H 5 AF 100 cos(1000r) 100 2 0.1 H 40) 4=414.12-45 A 12=1120 A 14,(1)=1414Cos(10001-45) mA 1,0 1000Cos(10001) mA 4-1.4142-45 mA

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Using mesh currents analysis technique finds the current i1 and iz of the circuit described in fig. 3.
0.1 H
5 AF
100 cos(1000r)
100 2
0,1 H
4=414.12-45* A
12=1120 A
4,(1)=1414Cos(10001-45) mA
12()=1000Cos(10001) mA
4-1.4142-45" mA
12=120 mA
None of the above
Transcribed Image Text:Using mesh currents analysis technique finds the current i1 and iz of the circuit described in fig. 3. 0.1 H 5 AF 100 cos(1000r) 100 2 0,1 H 4=414.12-45* A 12=1120 A 4,(1)=1414Cos(10001-45) mA 12()=1000Cos(10001) mA 4-1.4142-45" mA 12=120 mA None of the above
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