Using MDM, what is the reaction at support B? 4 kN 20 kN 18 kN 4 kN/m B D 2m 6m 2m 2m 4m Select one: Оа 1935 кN O b. 21.50 kN O C. 26.28 kN O d. 23.89 kN

Q: I0 KN 15 KN 10 KN E. 0.9 m C. 0.9m G IF 1.2m 1.2m 1.2m 1.2m

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Q: SITUATION 5. For Items 12-14. 12. Find the force acting on member FE. a. 1.803 kN "T" 1.Şm H b.…

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Q: 4.24-4.47 Construct the shear force and bending moment diagrams 2009 09+30 +4°,03 04+ 400 POTOM DOD…

A: GIVEN DATA:-⇒One sided over hanging beam of span= 10m⇒UDL:-⇒UDL on A-B portion= 7 KN/m⇒UDL on B-C…

Q: TOKN 2OKN 30m 20KN 36KN 36KN 36 KN 36KN 150m 5 out 3om = Problems : Find the reactions for all of…

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Q: need the answer quickly

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Q: A plug sits in a hole in the side of a tank. z = 2 m, ro-ring = 0.2 m, rplug = 0.25 m. O-ring 2 m…

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Q: Using MDM, what is the reaction at support A? 4 kN 20 kN 18 kN 4 kN/m B C. 2m 6m 2m 2m 4m 2m Select…

A: Finding out reaction at support A.

Q: h=8m A 1 kN F C El G 5 kN 5 kN 5 kN 1 kN D B 1 kN H 13. Calculate the force at member Gl O a.…

A: Given data in question  Point load  Span member length  To find out  Force in member GI

Q: need the answer quickly

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Q: Using MDM, what is the reaction at support D? 4 kN 20 kN 18 kN 4 kN/m A B C. D 2m 6m 2m 2m 4m Select…

A: Finding out reaction at support D.

Q: Fluid mechanics, I need solutions in 15 minutes please. MCQ/Determine the magnitude of the force…

A: If any force is acting on a body due to fluid, then the force will act on centroid of that body.The…

Q: What is the support moment M, in the beam shown below? 15KN 30 kN/m -1.5 m 1.5 m

A: UVL of 30 KN/m for 1.5 m lengthA concentrated load of 15 KN at the end of beamCorrect option is…

Q: Using MDM, what is the reaction at support C? 4 kN 20 kN 18 kN 4 kN/m A C. D 2m 6m 2m 2m 4m 2m…

A: Finding out reaction at support C.

Q: Find: a. b. c. Situation 4: Considering the beam provided below, fixed support at point A, an…

A: As per guidelines, first three sub parts have been solved.

Q: 4) The strength of the longitudined joint.of cylindrical tenk In the Fig.bellow.is 33 kips/it,…

A: Given data : For Longitudinal Joint:Hoop stress (σh)=33 kips/ftFor girth joint :Longitudinal stress…

Q: Problem Number 5 h = 8 m A 1 kN F B C E G 5 kN 5 kN 5 kN 1 kN 1 kN 1 kN K -6 panels @ 5 m = 30 m- D…

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Q: 4) Determine the absolute maximum moment in the beam due to the loading shown.

A: To determine:The absolute maximum moment in the beam due to the loading shown.

Q: Find roller support reaction

A: Given data : The value of Point load P=18 KN The value of uniformly varying load w=0 to 3 KN/m…

Q: Q1-for the Structure shown,Draw the bending moment and shearing force Diagrams: 30 kN 5KN/m 4m +3+

A: The following figure shows the Free Body Diagram of the beam.

Q: 30 kN C a 1m E b e 20 kN/m 8m HO- f 20,KN g 10 kN/m 6.0 2m 2m 2m ↓2m↓

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Q: : Using unit load method find the rotations at C

A: ###Determination  of Rotations At C ###Using  Unit load method##

Q: For the question calculate the reaction Draw normal.share and moment diagrama, Question 3: 10 kN/m 8…

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Q: F1 5 KN F2 13 kN e-45 P60 F3 4 kN 4 m 8 m F4 = 22 kN a 30 F5 = 4 kN 1] What is the resultant moment…

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Q: horizontal th

A: solution of above problem is below:

Q: 12 kN 8 kN C 1 m 3 m 1 m

A: Apply equilibrium condition : ∑MC=0RA×4-12×3+8×1=0RA=7 KN

Q: 1. FROM THE GIVEN TRUSS, DET. THE FF: a. HORIZONTAL REACTION @ J b. VERTICOL REACTION @ J C.…

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Q: Compute the reaction of the roller support of Beam CD. (3 Points) 10 KN 20 KN / m 5 KN / m A B 5 KN…

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Q: m m 2m AD Im 1.5m -15m 3 kN 4 kN 2m

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Q: 201 3m 30gge 40 KN.M 2m ditation 4 p 600 3m 2m 8m B INTERNAL HINGE C 2m 2m 2m 30 2m 60⁰ 3m KES 3mm…

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Q: 15kN/m . -3m 4 1SKN loku/m +3m Draw the shear and moment diagrom Section of Beam 150mm find the…

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Q: F1 = 3 kN F2 - 11 kN C. F3= 2 kN e-60 30 2m 7 m F4 = 20 kN D ElJa- 30 FS = 2 kN 1] What is the…

A: Given data  Length of the span Point loads Angles of these point loads.

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.