Using MATLAB Programming to solve this program **Step 1: Taylor Series Expansions for Cosine and Sine**Given the following Taylor series expansions for cosine and sine, create a program (using a for loop) to determine tan(x), where x is a value from 0 < x < π/2.\[ \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots = \sum_{k=0}^{n} \frac{(-1)^k x^{2k}}{(2k)!} \]\[ \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots = \sum_{k=0}^{n} \frac{(-1)^k x^{2k+1}}{(2k+1)!} \]This is a mathematical representation of the cosine and sine functions using their Taylor series. The Taylor series is an infinite sum of terms calculated from the values of the function's derivatives at a single point.**Explanation of the Equations:**1. **Cosine Series:** - The cosine of x, denoted as cos(x), is approximated by an infinite sum. - Each term in the series is derived from the derivatives of cos(x) at x = 0. - The general term is \(\frac{(-1)^k x^{2k}}{(2k)!}\), where k is the term index. 2. **Sine Series:** - The sine of x, denoted as sin(x), is also represented by an infinite sum. - Similarly, each term is derived from the derivatives of sin(x) at x = 0. - The general term is \(\frac{(-1)^k x^{2k+1}}{(2k+1)!}\), where k is the term index. These series provide a way to compute trigonometric functions for values of x using polynomial approximations, which can be useful in writing programs to calculate these functions numerically.

Sinx :function sinx = mysin(x,n)sinx=x;for i=1:n addterm = ((-1)^i)*(x^(2*i+1))/factorial(2*i+1); %taylor expansion sinx = sinx + addterm;endendCosx:function cosx = mycos(x,n)cosx=1;for i=1:n addterm = ((-1)^i)*(x^(2*i))/factorial(2*i); cosx = cosx + addterm;endendtanx:function plotterTan(~,n)count = 0;figure(1) while count < 3 xval = 1 for deg = 0:0.1:pi/2 sinx = mysin(deg,n); cosx = mycos(deg,n); tanx = sinx/cosx; plot(deg,tanx,'o'); xlabel('degrees(radians)') ylabel('tanx') hold all pause(0.1); xval = xval +1; end count = count +1; end hold offend