Using Linearization to Approximate Function Values We will create a linearization to approximate the value of V12. To create the linearization you will need the first derivative of the function f(x) = Vx and to What is f(9) ? What piece of information does this value give you as you create your tangent line? judge whether your approximation is an over- or under- estimate, you will need the second derivative. These derivatives are: f'(x) = 1 2vx f"(x) = -1 16x3 %3D What is f'(9) ? What piece of information does this value give you as you create your tangent line? A number that is close to 12 whose square root is easy to calculate is 9. We will create our linearization of f at x= 9. To start the process we must build our tangent line at x = 9 , which means we need to know the coordinates of the point of tangency at x = 9 and the slope of the tangent line. Submit

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
Using Linearization to Approximate Function Values
We will create a linearization to approximate the value
of v12. To create the linearization you will need the
first derivative of the function f(x) = Vx and to
What is f(9) ? What piece of information does this
value give you as you create your tangent line?
judge whether your approximation is an over- or under-
estimate, you will need the second derivative. These
derivatives are:
1
f'(x) =
Via
1.
f"(x) =
What is f'(9) ? What piece of information does this
16x3
value give you as you create your tangent line?
A number that is close to 12 whose square root is easy
to calculate is 9. We will create our linearization of f
at x= 9. To start the process we must build our
tangent line at x=9, which means we need to know
the coordinates of the point of tangency at x= 9 and
the slope of the tangent line.
Submit
Transcribed Image Text:Using Linearization to Approximate Function Values We will create a linearization to approximate the value of v12. To create the linearization you will need the first derivative of the function f(x) = Vx and to What is f(9) ? What piece of information does this value give you as you create your tangent line? judge whether your approximation is an over- or under- estimate, you will need the second derivative. These derivatives are: 1 f'(x) = Via 1. f"(x) = What is f'(9) ? What piece of information does this 16x3 value give you as you create your tangent line? A number that is close to 12 whose square root is easy to calculate is 9. We will create our linearization of f at x= 9. To start the process we must build our tangent line at x=9, which means we need to know the coordinates of the point of tangency at x= 9 and the slope of the tangent line. Submit
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