Using Kirchhoff's current law, find the unknown currents for the configurations in Figure. | 6 A 5 A 13 b | 2 A ЗА = 3 A d 10 A I4

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**Transcription and Explanation of Circuit Configuration**

**Text:**
Using Kirchhoff's current law, find the unknown currents for the configurations in the figure.

**Diagram Details:**
The figure illustrates an electrical circuit with multiple branches and current sources. The notable elements and junctions in the circuit are as follows:

1. **Junction a:**
   - Two currents entering: 6A and 2A (both downward).
   - A current, \(I_1\), leaves via a resistor towards junction b.

2. **Junction b:**
   - A current of 5A enters from above.
   - The current, \(I_1\), enters from junction a.
   - \(I_2\) leaves via a resistor towards junction c.

3. **Junction c:**
   - The current \(I_2\) enters from junction b.
   - \(I_3\) exits upward.
   - A battery, emitting a current of 3A, is connected between junctions c and d.

4. **Junction d:**
   - A current of 3A enters from the battery (upward into d).
   - A current of 10A leaves junction d to the left, towards junction c.
   - \(I_4\) is shown exiting to the right.

**Analysis Required:**
Using Kirchhoff's current law (KCL), which states that the sum of currents entering a junction equals the sum of currents leaving, apply KCL to junctions to solve for unknown currents \(I_1\), \(I_2\), \(I_3\), and \(I_4\). 

For example:
- At junction a: \(6A + 2A = I_1\).
- At junction b: \(I_1 + 5A = I_2\).
- At junction c: \(I_2 + 3A = I_3\).
- At junction d: \(3A = 10A + I_4\).

Apply these principles to solve for the unknown currents in the circuit.
Transcribed Image Text:**Transcription and Explanation of Circuit Configuration** **Text:** Using Kirchhoff's current law, find the unknown currents for the configurations in the figure. **Diagram Details:** The figure illustrates an electrical circuit with multiple branches and current sources. The notable elements and junctions in the circuit are as follows: 1. **Junction a:** - Two currents entering: 6A and 2A (both downward). - A current, \(I_1\), leaves via a resistor towards junction b. 2. **Junction b:** - A current of 5A enters from above. - The current, \(I_1\), enters from junction a. - \(I_2\) leaves via a resistor towards junction c. 3. **Junction c:** - The current \(I_2\) enters from junction b. - \(I_3\) exits upward. - A battery, emitting a current of 3A, is connected between junctions c and d. 4. **Junction d:** - A current of 3A enters from the battery (upward into d). - A current of 10A leaves junction d to the left, towards junction c. - \(I_4\) is shown exiting to the right. **Analysis Required:** Using Kirchhoff's current law (KCL), which states that the sum of currents entering a junction equals the sum of currents leaving, apply KCL to junctions to solve for unknown currents \(I_1\), \(I_2\), \(I_3\), and \(I_4\). For example: - At junction a: \(6A + 2A = I_1\). - At junction b: \(I_1 + 5A = I_2\). - At junction c: \(I_2 + 3A = I_3\). - At junction d: \(3A = 10A + I_4\). Apply these principles to solve for the unknown currents in the circuit.
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