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Using Integration By Parts, x Arcsec 3x dx=uv- -Svdu 了 Find uv- x² Arcsec 3x – 2 dx 2 x²-1 3 x Arcsec 3x= dx J2 9x2-1 dx x² Arcsec 3x - x² – 1 dx x² Arcsec 3x 2 V9x2-1

Using Integration By Parts, x Arcsec 3x dx=uv- -Svdu 了 Find uv- x² Arcsec 3x – 2 dx 2 x²-1 3 x Arcsec 3x= dx J2 9x2-1 dx x² Arcsec 3x - x² – 1 dx x² Arcsec 3x 2 V9x2-1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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SXArcsed Using Integration By Parts, Sva 3x dx-uv- Find v du UV- x2 Arcsec 3x 2 dx x²- 1 x Arcsec 3x = dx 2 V9x2 -1 1. x² Arcsec 3X dx x² - 1 1. dx x Arcsec 3x - 2 V9x2-1 m/2 1/2
Transcribed Image Text:SXArcsed Using Integration By Parts, Sva 3x dx-uv- Find v du UV- x2 Arcsec 3x 2 dx x²- 1 x Arcsec 3x = dx 2 V9x2 -1 1. x² Arcsec 3X dx x² - 1 1. dx x Arcsec 3x - 2 V9x2-1 m/2 1/2
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