Using induction, prove that 5|62n) – 1 for n = 1, 2, 3, ... %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:**Problem Statement:**
Using induction, prove that \(5 | (6^{(2n)} - 1)\) for \(n = 1, 2, 3, \ldots\)
**Explanation:**
This mathematical statement asks to prove that for any natural number \(n\), the expression \(6^{2n} - 1\) is divisible by 5. To demonstrate this, you will need to apply the principle of mathematical induction.
**Steps to Approach the Problem:**
1. **Base Case:**
- Check if the statement holds for \(n = 1\).
2. **Inductive Step:**
- Assume the statement is true for \(n = k\).
- Prove it for \(n = k + 1\).
**Key Points:**
- **Base Case:** Verify if \(5 | (6^{2 \times 1} - 1)\).
- **Inductive Hypothesis:** Assume \(5 | (6^{2k} - 1)\).
- **Inductive Conclusion:** Show \(5 | (6^{2(k+1)} - 1)\).
By following these steps, you will establish the proof using mathematical induction.
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