Using induction, prove that 5|62n) – 1 for n = 1, 2, 3, ... %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement:**

Using induction, prove that \(5 | (6^{(2n)} - 1)\) for \(n = 1, 2, 3, \ldots\)

**Explanation:**

This mathematical statement asks to prove that for any natural number \(n\), the expression \(6^{2n} - 1\) is divisible by 5. To demonstrate this, you will need to apply the principle of mathematical induction.

**Steps to Approach the Problem:**

1. **Base Case:**
   - Check if the statement holds for \(n = 1\).

2. **Inductive Step:**
   - Assume the statement is true for \(n = k\).
   - Prove it for \(n = k + 1\).

**Key Points:**

- **Base Case:** Verify if \(5 | (6^{2 \times 1} - 1)\).
- **Inductive Hypothesis:** Assume \(5 | (6^{2k} - 1)\).
- **Inductive Conclusion:** Show \(5 | (6^{2(k+1)} - 1)\).

By following these steps, you will establish the proof using mathematical induction.
Transcribed Image Text:**Problem Statement:** Using induction, prove that \(5 | (6^{(2n)} - 1)\) for \(n = 1, 2, 3, \ldots\) **Explanation:** This mathematical statement asks to prove that for any natural number \(n\), the expression \(6^{2n} - 1\) is divisible by 5. To demonstrate this, you will need to apply the principle of mathematical induction. **Steps to Approach the Problem:** 1. **Base Case:** - Check if the statement holds for \(n = 1\). 2. **Inductive Step:** - Assume the statement is true for \(n = k\). - Prove it for \(n = k + 1\). **Key Points:** - **Base Case:** Verify if \(5 | (6^{2 \times 1} - 1)\). - **Inductive Hypothesis:** Assume \(5 | (6^{2k} - 1)\). - **Inductive Conclusion:** Show \(5 | (6^{2(k+1)} - 1)\). By following these steps, you will establish the proof using mathematical induction.
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