Using Fixed-Point Iteration with an initial value of zero, find a root of the function: f(x) = x³ - 6x² + 4x + 2 Stop iteration when the approximate error is less than 0.5%. Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places Hint: First, equate the function to 0. Then, isolate the constant term. Next, factor "x" on the left side of the equation. Finally, isolate x by dividing the equation by the factor of "x" on the left side of the equation. So, the iterative formula will be Xk+1 = constant / (a certain expression with xk ) For example: k+1 -7 x+9xx-3 O -0.32795 O -0.32921 O none of the choices O-0.32875 -0.32892
Using Fixed-Point Iteration with an initial value of zero, find a root of the function: f(x) = x³ - 6x² + 4x + 2 Stop iteration when the approximate error is less than 0.5%. Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places Hint: First, equate the function to 0. Then, isolate the constant term. Next, factor "x" on the left side of the equation. Finally, isolate x by dividing the equation by the factor of "x" on the left side of the equation. So, the iterative formula will be Xk+1 = constant / (a certain expression with xk ) For example: k+1 -7 x+9xx-3 O -0.32795 O -0.32921 O none of the choices O-0.32875 -0.32892
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Using Fixed-Point Iteration with an initial value of zero, find a root of the function:
f(x) = x³ - 6x² + 4x + 2
Stop iteration when the approximate error is less than 0.5%.
Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places
Hint: First, equate the function to 0. Then, isolate the constant term. Next, factor "x" on the left side of the
equation. Finally, isolate x by dividing the equation by the factor of "x" on the left side of the equation.
So, the iterative formula will be Xk+1 = constant / (a certain expression with xk)
For example: k+1
-7
+92-3
O -0.32795
O -0.32921
O none of the choices
O -0.32875
-0.32892
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