Using Fixed-Point Iteration with an initial value of 3.5, find a value of x that will make the following function true with an error of less than 0.1%. f (2) = 3x² – e* = 0 Round-off intermediate values to 8 decimal places, and the final answer to 6 decimal places. Hint: First, isolate the " e" term. Then, "LN" of both sides of the equation. So, the iterative formula will be x+1 = LN(constant) + LN (a certain expression with x, ). For example: Tk+1 = In(8) + 6 In(rk) Recall: In(AB) = InA + InB and In(c) = din(c) 3.732170 3.731383 none of the choices 3.727177 3.732592 3.729915

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Which among the choices is the correct answer?

Using Fixed-Point Iteration with an initial value of
3.5, find a value of x that will make the following
function true with an error of less than 0.1%.
f (x) = 3r – e" = 0
Round-off intermediate values to 8 decimal places,
and the final answer to 6 decimal places.
Hint: First, isolate the "e" term. Then, "LN" of
both sides of the equation.
So, the iterative formula will be x+1 = LN(constant)
+ LN (a certain expression with x, ).
For example: ak+1 = In(8) + 6 In(rk)
Recall: In(AB) = InA + InB and In(c) din(c)
3.732170
3.731383
none of the choices
3.727177
3.732592
3.729915
Transcribed Image Text:Using Fixed-Point Iteration with an initial value of 3.5, find a value of x that will make the following function true with an error of less than 0.1%. f (x) = 3r – e" = 0 Round-off intermediate values to 8 decimal places, and the final answer to 6 decimal places. Hint: First, isolate the "e" term. Then, "LN" of both sides of the equation. So, the iterative formula will be x+1 = LN(constant) + LN (a certain expression with x, ). For example: ak+1 = In(8) + 6 In(rk) Recall: In(AB) = InA + InB and In(c) din(c) 3.732170 3.731383 none of the choices 3.727177 3.732592 3.729915
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