Using Fixed-Point Iteration with an initial value of 1, find a value of x that will make the following function true with an error of less than 1%: h(x) = x² + 2x² - x = 3 Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places. Hint: First, isolate the "x4" term. Then, get the fourth root of both sides of the equation. So, the iterative formula will be Xk+1 = fourth root (a certain expression with xk). For example: +1 = a cetain expression in terms of Ik 1.12554 O 1.12786 O 1.12181 O none of the choices O 1.11800 O 1.12325 Maud

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter11: Exponential And Logarithmic Functions
Section11.CR: Review Problem Set
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Using Fixed-Point Iteration with an initial value of 1, find a value of x that will make the
following function true with an error of less than 1%:
h(x) = x² + 2x² - x = = 3
Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places.
Hint: First, isolate the "x4" term. Then, get the fourth root of both sides of the equation.
So, the iterative formula will be Xk+1= fourth root (a certain expression with xk).
For example: +1 = √a cetain expression in terms of k
O 1.12554
O 1.12786
O 1.12181
O none of the choices
O 1.11800
O 1.12325
t
P
Transcribed Image Text:Using Fixed-Point Iteration with an initial value of 1, find a value of x that will make the following function true with an error of less than 1%: h(x) = x² + 2x² - x = = 3 Round-off intermediate values to 7 decimal places, and the final answer to 5 decimal places. Hint: First, isolate the "x4" term. Then, get the fourth root of both sides of the equation. So, the iterative formula will be Xk+1= fourth root (a certain expression with xk). For example: +1 = √a cetain expression in terms of k O 1.12554 O 1.12786 O 1.12181 O none of the choices O 1.11800 O 1.12325 t P
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