Using either logarithms or a graphing calculator, find the time required for the initial amount to be at least equal to the final amount. $7000, deposited at 8% compounded quarterly, to reach at least $9000 ..... The time required is year(s). (Type an integer or decimal rounded up to the next quarter.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement:**

Using either logarithms or a graphing calculator, find the time required for the initial amount to be at least equal to the final amount.

**Scenario:**
- $7000, deposited at 8% compounded quarterly, to reach at least $9000.

**Solution:**
- The time required is [ ] year(s).
  
*Note: Type an integer or decimal rounded up to the next quarter.*

**Explanation:**

To solve this, use the compound interest formula:

\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \]

Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount ($7000).
- \( r \) is the annual interest rate (0.08 for 8%).
- \( n \) is the number of times that interest is compounded per year (4 for quarterly).
- \( t \) is the time the money is invested for in years.

Set \( A = 9000 \) and solve for \( t \) to find the time required for the amount to reach at least $9000. Use logarithms if solving algebraically, or input the values into a graphing calculator to find \( t \). Round up to the nearest quarter as instructed.
Transcribed Image Text:**Problem Statement:** Using either logarithms or a graphing calculator, find the time required for the initial amount to be at least equal to the final amount. **Scenario:** - $7000, deposited at 8% compounded quarterly, to reach at least $9000. **Solution:** - The time required is [ ] year(s). *Note: Type an integer or decimal rounded up to the next quarter.* **Explanation:** To solve this, use the compound interest formula: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount ($7000). - \( r \) is the annual interest rate (0.08 for 8%). - \( n \) is the number of times that interest is compounded per year (4 for quarterly). - \( t \) is the time the money is invested for in years. Set \( A = 9000 \) and solve for \( t \) to find the time required for the amount to reach at least $9000. Use logarithms if solving algebraically, or input the values into a graphing calculator to find \( t \). Round up to the nearest quarter as instructed.
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