Using dimensional analysis, solve the following. How many grams of PbCl2 will precipitate when 5.75 g of Pb(NO3)2 react with excess KCl in solution? Balance the reaction equation ___Pb(NO3)2 + ___KCl --> ___PbCl2 + ___KNO3 Given 1 mol Pb(NO3)2 = 331.2 g Pb(NO3)2 1 mol PbCl2 = 278.1 g PbCl2

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Using dimensional analysis, solve the following.

How many grams of PbCl2 will precipitate when 5.75 g of Pb(NO3)2 react with excess KCl in solution?

Balance the reaction equation

___Pb(NO3)2 + ___KCl --> ___PbCl2 + ___KNO3

Given

  • 1 mol Pb(NO3)2 = 331.2 g Pb(NO3)2
  • 1 mol PbCl2 = 278.1 g PbCl2
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