Using cross product find the moment about point A due to 10 kN force shown. 10 KN 300 mm 30° 400 mm Select one: O -1.96k kNm O -1.96k kNm anticlockwise O 4.96k kNm O (1.5i - 3.46j) kNm
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- Determine the magnitude of the moment about the line "og" of a force of 12 N in the defined direction from point "f" to "b". Where x = 1.4 m, y = 3.9 m, z = 4.8 mNE Chapter 10, Problem 062 Z Your answer is partially correct. Try again. In the figure, three 0.07 kg particles have been glued to a rod of length L = 5 cm and negligible mass and can rotate around a perpendicular axis through point O at one end. How much work is required to change the rotational rate (a) from 0 to 20.0 rad/s, (b) from 20.0 rad/s to 40.0 rad/s, and (c) from 40.0 rad/s to 60.0 rad/s? (d) What is the slope of a plot of the assembly's kinetic energy (in joules) versus the square of its rotation rate (in radians-squared per second-squared)? Axis (a) Number Units 0.0010110 (b) Number Units 0.030 (c) NumberTo.050 Units (d) Number UnitšT kg-m 2 m Click if you would like to Show Work for this question: Open Show Work emA block of 50 kg is attached to a cable. The cable is then attached to a rotating assembly with a mass moment of inertia of 10 kg-m^2. The bearing friction applied at the rotating assembly is equivalent to a couple of 50 N-m CCW. The block's initial downward speed is 1 m/s. 0.5 m 50 kg 3. Which of the following is closest to the work done by the weight of the 50-kg block after the rotating assembly has rotated 0.8 radians CW? 196.2 J 105.7 J -196.2 J -135.4 J he following is closest to the total work done by the system after the rotating rotated 0.8 rad CW? 5. Which of the following is closest to the speed of the 50-kg block after the rotating assembly rotated 0.8 rad CW?
- Determine the moment produced by the force F = 0.578 i +2.376 j - 1.376 k, and the position vector r= 4i + 10j - 3k Select one: -6.632i +3.77j +3.724k +2.64i - 7.08j - 2.968k -5.74i - 3.208j -10.68k - 3.64i +29.238j +18.568k NoneAn isolated system consists of a single object, which initially moves without friction at velocity ux along a horizontal x-axis. After an internal explosion, the object splits into two parts, A and B. The figure shows the masses and speeds of these parts immediately after the explosion. None of these objects rotates. 1.50 m s-¹ 2.00 kg A Final kinetic energy initial kinetic energy 3.50 m s-¹ - 3.00 kg What is the difference between the total final kinetic energy of A and B and the initial kinetic energy of whole object? Give you answer by entering a number, specified to an appropriate number of significant figures, into the empty box. B J.90 N 40° L=1m 80 N 37° A 1/4 L 3/4 60 N The moment of force about A is approximately 37 Nm counterclockwise 54.7 Nm counterclockwise 29 Nm counterclockwise 12 Nm counterclockwise 70 N B 30° 50 N
- Determine the magnitude of the moment about the line "og" of a force of 11 N in the defined direction from point "f" to "b". Where x = 2.2 m, y = 2.5 m, z = 5.7 mIf the skater has the same speed of rotation during the following spin positions, what is the correct ranking of their angular momentum? KOSE KO KOSE KO KOS KOSÉ #1 #2 #3 L#1=L#3L#2>L#3 L#1=L#2=L#3 OL#1Two solid spheres of radius R and mass m are initially separated by a distance d such that the two centres of mass are separated by d+3R as shown below. The spheres are initially at rest, but the gravitational force accelerates them towards each other until they collide.a) Calculate the initial mechanical energy of the system.b) Calculate the gravitational potential energy of the system at the moment they collide.c) Derive an expression for v. State carefully what physical law you are applying.d) Show that, in the limit d >> R, the velocity v is independent of d.Sl units of bending moment is kN^2 O kN.m km O kNZ solvedexa... -> Sheet (2) Solved examples (Moment Analysis) Ex/1 (a) Calculate the moment of the 90-N force about point O for the condition 6 15°. Also, determine the value of 0 for which the moment about O is (b) zero and (c) a maximum. (a) e - 15* FM. = 10cos1s" (0.6)-losin 15 (22) = 33.5 N'm 10 N 800 F- 90 N 800 mm mm 600 (b) e- tan ( - 36.1 600 mm ...Part A Determine the magnitude of the moment produced by force F = {-5i+6j + 9k} N about the diagonal axis AF of the rectangular block(Figure 1). ΑΣΦ ? vec MAF N.m %3D 1 of 1 В A 1.5 m 3 m 3 m