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Using Coefficient Linear in Two Variable, solvethe solution of the differential equation; (x– 2y + 3)dx+ (4x+ y + 3)dy = 0 а. (x + у)Inc(x +у) — -3(у— 1) с. (х — у)ln c(x +у) — 3(у— 1) b. (х - у)lincCx - у)- 3(у+ 1) d. (x + y)In c(x + y) = -3(y+ 1) e. none of the choices

Using Coefficient Linear in Two Variable, solvethe solution of the differential equation; (x– 2y + 3)dx+ (4x+ y + 3)dy = 0 а. (x + у)Inc(x +у) — -3(у— 1) с. (х — у)ln c(x +у) — 3(у— 1) b. (х - у)lincCx - у)- 3(у+ 1) d. (x + y)In c(x + y) = -3(y+ 1) e. none of the choices

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using Coefficient Linear in Two Variable, solvethe solution of the differential equation; (x- 2y + 3)dx+ (4x + y + 3)dy = 0 a. (x + y)In c(x + y) = -3(y – 1) с. (х — у) In c(x +у) — 3(у— 1) b. (x — у)In c(x -у) — 3(у+ 1) d. (x + y)lnc(x + у) — —3(у+ 1) e. none of the choices
Transcribed Image Text:Using Coefficient Linear in Two Variable, solvethe solution of the differential equation; (x- 2y + 3)dx+ (4x + y + 3)dy = 0 a. (x + y)In c(x + y) = -3(y – 1) с. (х — у) In c(x +у) — 3(у— 1) b. (x — у)In c(x -у) — 3(у+ 1) d. (x + y)lnc(x + у) — —3(у+ 1) e. none of the choices
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