Using appropriate substitution, f sin°(x)cos³ (x)dx is equal to:

Q: aluate 4e3 tan z sec2 x dx.

A:

Q: Evaluate fsin (2xv1-x) dx.

A:

Q: Find a “nice" (i.e. algebraic) expression for tan(sec-1(t)) for negative t-values.

A: We have to find

Q: Apply Newton’s approx. to find the value of x for cos x = sin x; x0 = 1.

A: Topic-  Numerical Analysis. Newton's approximation Formula: xn+1 = xn - f ( xn)f' (xn)

Q: 5. Use substitution to find S sin1º0 cos 0 d0.

A: We will find the integration.

Q: Use the method of substitution to evaluate | 2x cos x? dx.

A:

Q: Find the W (sinx,cosx , sec x).

A:

Q: Verify. esc (x) [I-cos(2x)] = 2 sin (x) SC

A:

Q: Find the following derivative: dx sin tdt O A. - sinx O B. sin x О с. 1 cos X O D. 3 cos X

A:

Q: q. [sec' x/1 + tan x dx

A:

Q: +cos x dx =?

A:

Q: Evaluate sin (x) cos“(x) dx.

A: ∫ππsin6x cos4x dx

Q: dx It sin x-cos x COS

A: To evaluate:∫dx1+sinx-cosx Solution: We know,cos2x=1-tan2x1+tan2x     ...(1)sin2x=2tanx1+tan2x…