Using a suitable trigonometric substitution, the integral dx 3 (16x² + 9)² is equal to sin 8+ C₁-<< 12 the above

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using a suitable trigonometric substitution, the integral
is equal to
TT
- C,
sin 0 + C₁ - <0<
12
2
the above
dx
3
(16x² + 9)²
36
sin 0+ C₁-<0<
2
TU
Transcribed Image Text:* Using a suitable trigonometric substitution, the integral is equal to TT - C, sin 0 + C₁ - <0< 12 2 the above dx 3 (16x² + 9)² 36 sin 0+ C₁-<0< 2 TU
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