Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3262.5 g and a standard deviation of 846.7 g. Newborn females have weights with a mean of 3063.6 g and a standard deviation of 592.1 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1500 g or a female who weighs 1500 g? Since the z score for the male is z= and the z score for the female is z=, the V has the weight that is more extreme. (Round to two decimal places.)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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**Use z scores to compare the given values.**

Based on sample data, newborn males have weights with a mean of 3262.5 g and a standard deviation of 846.7 g. Newborn females have weights with a mean of 3063.6 g and a standard deviation of 592.1 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1500 g or a female who weighs 1500 g?

Since the z score for the male is \( z = \) [____] and the z score for the female is \( z = \) [____], the [____] has the weight that is more extreme.  
*(Round to two decimal places.)*

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Transcribed Image Text:**Use z scores to compare the given values.** Based on sample data, newborn males have weights with a mean of 3262.5 g and a standard deviation of 846.7 g. Newborn females have weights with a mean of 3063.6 g and a standard deviation of 592.1 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1500 g or a female who weighs 1500 g? Since the z score for the male is \( z = \) [____] and the z score for the female is \( z = \) [____], the [____] has the weight that is more extreme. *(Round to two decimal places.)* **Button:** Next There are no graphs or diagrams in the image.
Expert Solution
Step 1

For male:mean(μm)=3262.5standard deviation(σm)=846.7and xm=1500For female:mean(μf)=3063.6standard deviation(σf)=592.1and Xf=1500

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