-Use your value of Ke calculated with the Value alculate the value of Kc for the reaction Fe(SCN)2+ + SCN- +→ Fe(SCN)2+. (Think of the eroperties for combining equilibrium constants for multiple reactions.) Based on the quilibrium constant, is the formation of Fe(SCN)2+ favorable? Should we assume that no Te(SCN)2+is formed in our reaction? Why or why not?

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4. Use your value of Ke calculated with the value of Ke given in the introduction (Eq. 2) to
calculate the value of Kc for the reaction Fe(SCN)2+ + SCN- ++ Fe(SCN)2+. (Thỉnk of the
properties for combining equilibrium constants for multiple reactions.) Based on the
equilibrium constant, is the formation of Fe(SCN)2+ favorable? Should we assume that no
Fe(SCN)2+is formed in our reaction? Why or why not?
Volume of
Volume of
initial
initial conc
of Fe3+
conc of
SCN-
Equilibrium
Absorbance conc Fe(SCN)2+
0.0060M
0.0020M
volume of
Fe3+
SCN-
water
Kc
0.0003117
651.230
0.00047
0.00027
0.60
0.00340
0.196
1.70
2.00
0.70
0.40
0.60
0.00400
0.157
0.0002405
2442.436
1.60
0.80
0.60
0.00320
0.00053
0.193
0.0003062
465.905
1.30
1.00
0.70
0.00260
0.00067
0.116
0.0001656
135.776
1.00
1.30
0.70
0.00200
0.00087
0.211
0.0003391
386.952
Ke average - (651.230 + 2442.436+465.905 + 135.776 +386.952)/5-816.460
[Fe(SCN);]
Fe" (ag) + 2 SCN (aq) = Fe(SCN)2 (ag)
Kcz =
= 1.6 x 103
(2)
[Fe" ][SCN ]
Transcribed Image Text:4. Use your value of Ke calculated with the value of Ke given in the introduction (Eq. 2) to calculate the value of Kc for the reaction Fe(SCN)2+ + SCN- ++ Fe(SCN)2+. (Thỉnk of the properties for combining equilibrium constants for multiple reactions.) Based on the equilibrium constant, is the formation of Fe(SCN)2+ favorable? Should we assume that no Fe(SCN)2+is formed in our reaction? Why or why not? Volume of Volume of initial initial conc of Fe3+ conc of SCN- Equilibrium Absorbance conc Fe(SCN)2+ 0.0060M 0.0020M volume of Fe3+ SCN- water Kc 0.0003117 651.230 0.00047 0.00027 0.60 0.00340 0.196 1.70 2.00 0.70 0.40 0.60 0.00400 0.157 0.0002405 2442.436 1.60 0.80 0.60 0.00320 0.00053 0.193 0.0003062 465.905 1.30 1.00 0.70 0.00260 0.00067 0.116 0.0001656 135.776 1.00 1.30 0.70 0.00200 0.00087 0.211 0.0003391 386.952 Ke average - (651.230 + 2442.436+465.905 + 135.776 +386.952)/5-816.460 [Fe(SCN);] Fe" (ag) + 2 SCN (aq) = Fe(SCN)2 (ag) Kcz = = 1.6 x 103 (2) [Fe" ][SCN ]
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