Use your knowledge of number systems to solve the problem given below (Please sho 1. Convert following Binary Numbers into Decimal (i) (ii) (11010)2 = ( (110101.11)2 = ( ho 2. Convert the following Hexadecimal Numbers into the base indicated (i) (i) (B65F)16 = ( Jao (3A6.C)1s = ( 2 3. Convert the following Decimal numbers into the base indicated: (i) (ii) (41.6875)10 = ( (106.16)10 = (
Use your knowledge of number systems to solve the problem given below (Please sho 1. Convert following Binary Numbers into Decimal (i) (ii) (11010)2 = ( (110101.11)2 = ( ho 2. Convert the following Hexadecimal Numbers into the base indicated (i) (i) (B65F)16 = ( Jao (3A6.C)1s = ( 2 3. Convert the following Decimal numbers into the base indicated: (i) (ii) (41.6875)10 = ( (106.16)10 = (
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Lab Task
Use your knowledge of number systems to solve the problem given below (Please show all intermediate steps):
1.
Convert following Binary Numbers into Decimal
(i)
(11010)2 = (
J10
(ii)
(110101.11)2 = (
Jao
2. Convert the following Hexadecimal Numbers into the base indicated
(i)
(ii)
(B65F)16 = ( )10
(3A6.C)16 = ( )2
3. Convert the following Decimal numbers into the base indicated:
(i)
(41.6875)10 = (
(ii)
(106.16)10 = (
J16
Unverity of
4. Perform the addition (59F)16 + (E46)16:
5. Using 2's complement, perform M-N with the following unsigned binary numbers. Also check the result by
performing subtraction directly.
M = 11010
(i)
N = 1101
(ii)
M= 11010
N= 10000
(iii)
M = 10010
N= 10011
6. Search the internet to learn about Gray Code. Write the binary and Gray Code for decimal numbers between 0
and 15.
7. Using 2's complement, perform M-N with the following signed 5-bit binary numbers. Also check the result by
performing subtraction directly.
M = 11010
M = 01010
M = 10010
N= 01101
N = 10000
N = 00001
(i)
(ii)
(iii)
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