Use variation of parameters to find a particular solution, given the solutions y1, Y2 of the complementary equation sin(x)y''+ (2 sin(x) – cos(x))y' + (sin(x) – cos(x))y = e=² OS Y1 = e-, 2 = e cos(x) COS Yp(x) = %3D

Q: (b) у" — 2у + у 3 еt sin(z)

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Q: Solve (sin(x) cos(y)) dx + (cos(x) sin(y))dy = 0 if possible. If the equation is not exact, say so.…

A: First we check given differential equation is exact or not.  If given differential equation is exact…

Q: Use variation of parameters to find a particular solution, given the solutions y 1, 2 of the…

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Q: f(x) = 3x cos ƒ'(x). -1 (2x + 4) − √√/19 − 3x², find

A: Given: fx=3xcos-12x+4-19-3x2. To Find: f'x.

Q: Solve the equation y' (t) + y(t) t dz -√4(z) Sin (t-2) d2 = - Sint yco) = 1

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Q: Solve y' = cos(2x + y – 5) – 2. = COS

A: The solution is given as

Q: s to find a particular sy1, y2 of the s(x))y'+(sin(x) - cos(x)) y = e 2 = e-* cos(x)

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Q: If y(t) is the general solution for the equation: y' + y = sin(t), y(pi/2) = 0 Then, y(0) = ? a)…

A: Consider the differential equation  y'+y=sint,           yπ2 = 0