use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2). that is numerator is 1 denominator is 3 t-squared times the square root of 6-t-squared. I tried letting t=square root of six times cosx. I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!
use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2). that is numerator is 1 denominator is 3 t-squared times the square root of 6-t-squared. I tried letting t=square root of six times cosx. I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!
use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2). that is numerator is 1 denominator is 3 t-squared times the square root of 6-t-squared. I tried letting t=square root of six times cosx. I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!
use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2).
that is numerator is 1
denominator is 3 t-squared times the square root of 6-t-squared.
I tried letting t=square root of six times cosx.
I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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