Use this equation to calculate the approximate speed of the space station given the distance between the centre of the Earth and the space station that you found in part (b). Note that the mass of the Earth (mearth) is 5.972 x 1024 kg. Report the speed in units of km/hour. How does this compare to the known average speed of the International Space Station, 27600 km/hour? If your result is not reasonably close to the actual speed, try repeating your calculation/check your work.
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
![f) Assume that the space station orbits the Earth with uniform circular motion. This means that the
magnitude of the acceleration of the space station is given by a = v²/r. In addition, the net force
on the space station is equal to m,tation*a (Newton's Second Law, as always), and the force on
the space station is F = - G*m,tation*Mearth/r?. Using these equations, we can derive a formula for
the speed of the space station as it orbits Earth:
Fnet = m*a (towards centre of earth for uniform circular motion)
Inserting Newton's Law of Universal Gravitation and the formula for centripetal acceleration,
G*mstation *mearth/r² = mstation*Vstation/r,
and dividing both sides by mstation and multiplying both sides by r, we get:
G*marth/r = v, and finally we arrive at our formula for the speed of the station,
Vstation = V(G*mearth/r), ...note that this is meant to be a square root symbol.
Use this equation to calculate the approximate speed of the space station given the distance
between the centre of the Earth and the space station that you found in part (b). Note that the
mass of the Earth (mearth) is 5.972 x 1024 kg. Report the speed in units of km/hour. How does this
compare to the known average speed of the International Space Station, 27600 km/hour? If
your result is not reasonably close to the actual speed, try repeating your calculation/check your
work.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F293a90f5-9a0a-497d-836f-c0d9b0a5c0f7%2Fc8da98fb-2879-4d63-b72b-7f7ea90edf2b%2Fcji43ad_processed.png&w=3840&q=75)
![Distance from earth to the space station is 6378 km
Distance from earth center to the earth surface is 6798 km](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F293a90f5-9a0a-497d-836f-c0d9b0a5c0f7%2Fc8da98fb-2879-4d63-b72b-7f7ea90edf2b%2Frrt8ug_processed.png&w=3840&q=75)
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