Use this balanced equation to solve the following problem:Na2CO3 (s) + 2 HCI (ag) -H20 m + CO2 (9)+ 2 Nacl (aq)8.13 grams of sodium carbonate are added to 0.015 moles of hydrochloric acid. How many grams of carbon dioxide will be produced? What is thelimiting reactant?Select one or more:O hydrochloric acid is limitingO sodium carbonate is limitingO both reactants are limitingO there is no limiting reactantO 0.33 g carbon dioxideO 0.66 g carbon dioxideO3.38 g carbon dioxideO 6.75 g carbon dioxideO 1.19 g carbon dioxideO 0.12 g carbon dioxideO 0.12 g carbon dioxideNex

Answered: Use this balanced equation to solve the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Use this balanced equation to solve the following problem:
Na2CO3 (s) + 2 HCI (ag) -
H20 m + CO2 (9)
+ 2 Nacl (aq)
8.13 grams of sodium carbonate are added to 0.015 moles of hydrochloric acid. How many grams of carbon dioxide will be produced? What is the
limiting reactant?
Select one or more:
O hydrochloric acid is limiting
O sodium carbonate is limiting
O both reactants are limiting
O there is no limiting reactant
O 0.33 g carbon dioxide
O 0.66 g carbon dioxide
O3.38 g carbon dioxide
O 6.75 g carbon dioxide
O 1.19 g carbon dioxide
O 0.12 g carbon dioxide
O 0.12 g carbon dioxide
Nex

Expert Solution

Step 1 GIVEN

molar mas of HCl=35.5g/mol.

number of moles of HCl=0.015moles.

molar mass of Na₂CO₃=106g/mol.

molar mass of CO₂=44g/mol.

REACTION

$N a_{2} C O_{3} + 2 H C l \underset{}{\to} H_{2} O + C O_{2} + 2 N a C l$

The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.

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