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Use these prime factorizations to compute the following quar Icm(1083, 15435) O 32.5.73. 192 = 5,572, 035 O 23 . 34 .5- 73 = 1, 111, 320 O 2 .5- 72 - 13 = 25, 480 O 22.5- 72 . 11 = 10,780 %3D

Use these prime factorizations to compute the following quar Icm(1083, 15435) O 32.5.73. 192 = 5,572, 035 O 23 . 34 .5- 73 = 1, 111, 320 O 2 .5- 72 - 13 = 25, 480 O 22.5- 72 . 11 = 10,780 %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use these prime factorizations to compute the following quantity: \[ \text{lcm}(1083, 15435) \] Options: - \(2^2 \cdot 5 \cdot 7^2 \cdot 11 = 10,780\) - \(2^3 \cdot 5 \cdot 7^2 \cdot 13 = 25,480\) - \(2^3 \cdot 3^4 \cdot 5 \cdot 7^3 = 1,111,320\) - \(3^2 \cdot 5 \cdot 7^3 \cdot 19^2 = 5,572,035\)
Transcribed Image Text:Use these prime factorizations to compute the following quantity: \[ \text{lcm}(1083, 15435) \] Options: - \(2^2 \cdot 5 \cdot 7^2 \cdot 11 = 10,780\) - \(2^3 \cdot 5 \cdot 7^2 \cdot 13 = 25,480\) - \(2^3 \cdot 3^4 \cdot 5 \cdot 7^3 = 1,111,320\) - \(3^2 \cdot 5 \cdot 7^3 \cdot 19^2 = 5,572,035\)
Expert Solution
Step 1

Rational Numbers: All the numbers which can be written in the form of pq. Here, p and q are integers and q is not equal to 0. Integers and fractions constitute rational numbers. Rational numbers are either terminating or recurring.

Irrational Numbers: These are non-terminating and non-recurring.

Real Numbers: All rational and irrational numbers constitute real numbers. Real numbers can be represented on a number line.

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