Use Theorem 9.2.1 to show that T is not continuous at 0, no matter what value is chosen for b.
Use Theorem 9.2.1 to show that T is not continuous at 0, no matter what value is chosen for b.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Analytical math

Transcribed Image Text:12:20 M
Use Theorem 9.2.1 to show that T is not
continuous at 0, no matter what value is
chosen for b.
Theorem 9.2.1. The function f is
continuous at a if and only if f satisfies
the following property:
V sequences (xn), if lim n = a then lii
in-context
Sketch of the Proof of Theorem 9.2.1.
We've seen how we can use
Theorem 9.2.1, now we need to prove
Theorem 9.2.1. The forward direction is
fairly straightforward. So we assume that
f is continuous at a and start with a
sequence (xn) which converges to a. What
is left to show is that lim,→0 f(xn) = f(a).
If you write down the definitions of f
being continuous at a, lim,- Xn = a, and
lim, +00 f(xn) = f(a), you should be able
to get from what you are assuming to
what you want to conclude.
To prove the converse, it is convenient to
prove its contrapositive. That is, we want
to prove that if ƒ is not continuous at a
then we can construct a sequence (x.)
>
II

Transcribed Image Text:12:19 M
Problem 9.2.5. The function
T(x) = sin (-) is often called the
topologist's sine curve. Whereas sin x has
roots at nr, n E Z and oscillates infinitely
often as x → ±∞, T has roots at
n E Z, n # 0, and oscillates infinitely
often as x approaches zero. A rendition
of the graph follows.
-0.5
0.5
15
Notice that T is not even defined at = 0.
We can extend T to be defined at 0 by
simply choosing a value for T(0) :
sin (+), if x 70
16,
T(x) =
if x =
Use Theorem 9.2.1 to show that T is not
continuous at 0, no matter what value is
chosen for b.
II
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