SOLUTION(A) Find the frequencies if the pipe is open at both ends.Substitute into whole harmonicsequation, with n = 1.Multiply to find the second and thirdharmonics.This works out to n = 286.88, whichmust be truncated down (n = 287gives a frequency over 2.00 x 104 Hz).The next two harmonics are oddmultiples of the first:(B) How many harmonics lie between 20 Hz and 20000 Hz for this pipe?Set the frequency in the harmonicsequation equal to 2.00 x 104 Hz andsolve for n.(C) Find the frequencies for the pipe closed at one end.Apply the one end open harmonicsequation with n = 1.f2=f3Vf₁ =-2Lf2 2f1= 139 HzVfn === n2Ln = 286Hz343 m/s2(2.46 m)f1HzVHz4L= 69.7 Hz343 m/s4(2.46 m)f33f1 = 209 Hz343 m/s2. (2.46 m)f3 = 3f₁ = 105 HzLEARN MOREQUESTION True or False: The fundamental wavelength of a longer pipe is greater than the fundamentalwavelength of a shorter pipe.True, because the fundamental wavelength is the length of the pipe.False, because the speed of sound is slower in the longer pipe.True. The exact relation depends on whether the pipe is closed at both ends, but longer pipes ofthe same kind have longer fundamental wavelength.True, because the fundamental wavelength is twice the length of the pipe.True, because the fundamental wavelength is half the length of the pipe.PRACTICE ITUse the worked example above to help you solve this problem. A pipe is 2.42 m long.(a) Determine the frequencies of the first three harmonics if the pipe is open at both ends. Take345 m/s as the speed of sound in air.f171.28Hz=2.00 x 104 Hz= 34.9 Hzf5 = 5f1 = 175 Hz0.56XYour response differs significantly from the correct answer. Rework your solution from thebeginning and check each step carefully. HzHz(b) How many harmonic frequencies of this pipe lie in the audible range, from 20 Hz to 20000 Hz?280(c) What are the three lowest possible frequencies if the pipe is closed at on end and open at theother?f1 =f3 =f5 =

Given data- Length of pipe L=2.42 m speed of sound in air v=345 m/s

Use the worked example above to help you solve this problem. A pipe is 2.42 m long.. (a) Determine the frequencies of the first three harmonics if the pipe is open at both ends. Take 345 m/s as the speed of sound in air. ✓ Hz fi = f2 = f3 = 71.28 0.56 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Hz Hz (b) How many harmonic frequencies of this pipe lie in the audible range, from 20 Hz to 20000 Hz? 280 (c) What are the three lowest possible frequencies if the pipe is closed at on end and open at the other? f1 = f3 = f5= Hz Hz Hz

Use the worked example above to help you solve this problem. A pipe is 2.42 m long.. (a) Determine the frequencies of the first three harmonics if the pipe is open at both ends. Take 345 m/s as the speed of sound in air. ✓ Hz fi = f2 = f3 = 71.28 0.56 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Hz Hz (b) How many harmonic frequencies of this pipe lie in the audible range, from 20 Hz to 20000 Hz? 280 (c) What are the three lowest possible frequencies if the pipe is closed at on end and open at the other? f1 = f3 = f5= Hz Hz Hz

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Only need to solve part c
Suppose you shake a slinky continuously in an up and down fashion such that a transverse waves propagate horizontally down its length. If you count 15 peaks have been made during a time of 2.03s, what is the frequency of the wave (in Hz)? V Note: In the space below, please enter you numerical answer. Do not enter any units. If you enter units, your answer will be marked as incorrect.
Refer to Figure 3. A room of dimensions L1-1.4 m, L2 2.9 m and L3- 3,4 m has rigid walls and is completely empty. What is the particle velocity in the middle of the x1 -1.4 m wall (x1-L1, x2- L2/2 and x3 - L3/2) knowing that speed of sound c- 348 m/s? Enter your answer with one decimal point in the form xx.x. QUESTION 13 X3 L3 X2 L2 X1 L1 Figure 3 – Rectangular enclosure. |
Give me correct answers
Solve the problems with complete solution.State also the given and box the final answer 1. The speed of a longitudinal wave in silver, density 10.5 x 10^3 kg/m^3, is 2610 m/s. Compute Young’s Modulus for silver. 2. If the Young’s Modulus of a metal rod is 1.2 x 10^10 N/m^2 and the speed of sound in this rod is 1160 m/s, find its density.
SOLUTION (A) Find the first three harmonics at the given tension. Calculate the speed of the wave on the wire: Find the wire's fundamental frequency: Find the next two harmonics by multiplication: = V = f₁ Substitute the values of F, μ, and L. F 1/2 80 N (=) ¹/² = (2.00 x 10-³ kg/m = (B) Find the wavelength of the sound waves produced. Solve vs fλ for the wavelength and substitute the frequencies. F == A V f₁ 2L (C) Find the fundamental frequency corresponding to the elastic limit. Calculate the tension in the wire from the elastic limit: f₁ f₂ = 2f₁ = 2.00 × 10² Hz, ƒ3 = 3ƒ₁ = 3.00 × 10² Hz A₁ = v₁/f₁ = (345 m/s)/(1.00 x 10² Hz) = 3.45 m 1₂ = vs/f₂ = (345 m/s)/(2.00 x 10² Hz) = 1.73 m ^₂ = vs/f3 = (345 m/s)/(3.00 x 10² Hz) = 1.15 m = 2.00 × 10² m/s 2(1.00 m) elastic limit →→ F = (elastic limit) A F = (2.80 x 108 Pa) (2.56 × 10-7m²) = 71.7 N 1 V 2L F 1/2 -= 1.00 x 10² Hz μ = 2.00 x 10² m/s 1 2(1.00 m) 71.7 N 2.00 x 10-³ kg/m = 94.7 Hz
A 1.1 m string oscillating at a frequency of 86 Hz generates the standing wave shown below. What is the wave speed on the string. What is the linear density on the string if the string tension is 5.6 N?
only type
O d. 5.40 Find the number of nodes and anti-nodes for the given standing waves formed on a stretched string. Select one: O a. 3 & 3 O b. 2 & 2 O c. 2 & 3 O d. 3 & 2 For the diagram shown below, find the wavelength of the wave
skip if you already did this
Needs Complete solution with 100 % accuracy.
Answer question 1b showing fully all the steps. Solution should be simplified and easy to understand as much as possible!