Use the worked example above to help you solve this problem. A diverging lens of focal length f = -8.1 cm forms images of an object situated at various distances. (a) If the object is placed p₁ = 24.3 cm from the lens, locate the image, state whether it's real or virtual, and find its magnification. 9-6.08 ✔ cm M = 0.25 (b) Repeat the problem when the object is at p2 = 8.1 cm. ✔ cm 9-4.05 M = 0.5 (c) Repeat the problem again when the object is 4.05 cm from the lens. -2.7 cm M = 0.6 The response you submitted has the wrong sign. EXERCISE HINTS: GETTING STARTED Use the values from PRACTICE IT to help you work this exercise. Repeat the calculation, finding the position of the image and the magnification if the object is 16.1 cm from the lens. x I'M STUCK! -16.3 9 You used an equation which correctly described the relationship between the image distance, object distance, and the focal length, but you made an algebraic mistake when solving for the image distance, cm 1.01 x M You used an equation which correctly described the relationship between the magnification and the = image and object distances, but your value for the image distance was incorrect, making this answer wrong too.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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use image to solve my incorrect mistakes 

Use the worked example above to help you solve this problem. A diverging lens of focal length f = -8.1 cm
forms images of an object situated at various distances.
(a) If the object is placed p₁ = 24.3 cm from the lens, locate the image, state whether it's real or
virtual, and find its magnification.
9 = -6.08
M = 0.25
(b) Repeat the problem when the object is at p2 = 8.1 cm.
9 = -4.05
M = 0.5
cm
M =
(c) Repeat the problem again when the object is 4.05 cm from the lens.
-2.7
✔ cm
cm
0.6
The response you submitted has the wrong sign.
EXERCISE
HINTS: GETTING STARTED
I'M STUCK!
Use the values from PRACTICE IT to help you work this exercise. Repeat the calculation, finding the
position of the image and the magnification if the object is 16.1 cm from the lens.
x
Submit Answer
-16.3
9 You used an equation which correctly described the relationship between the image distance, object
distance, and the focal length, but you made an algebraic mistake when solving for the image
distance. cm
1.01
x
M You used an equation which correctly described the relationship between the magnification and the
= image and object distances, but your value for the image distance was incorrect, making this answer
wrong too.
Transcribed Image Text:Use the worked example above to help you solve this problem. A diverging lens of focal length f = -8.1 cm forms images of an object situated at various distances. (a) If the object is placed p₁ = 24.3 cm from the lens, locate the image, state whether it's real or virtual, and find its magnification. 9 = -6.08 M = 0.25 (b) Repeat the problem when the object is at p2 = 8.1 cm. 9 = -4.05 M = 0.5 cm M = (c) Repeat the problem again when the object is 4.05 cm from the lens. -2.7 ✔ cm cm 0.6 The response you submitted has the wrong sign. EXERCISE HINTS: GETTING STARTED I'M STUCK! Use the values from PRACTICE IT to help you work this exercise. Repeat the calculation, finding the position of the image and the magnification if the object is 16.1 cm from the lens. x Submit Answer -16.3 9 You used an equation which correctly described the relationship between the image distance, object distance, and the focal length, but you made an algebraic mistake when solving for the image distance. cm 1.01 x M You used an equation which correctly described the relationship between the magnification and the = image and object distances, but your value for the image distance was incorrect, making this answer wrong too.
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