Use the value of the first integral I to evaluate the two given integrals. a. 3 || = √(x³ - 6x) dx = - 3 0 0 (12x-2x³) dx - 27 4 0 - b. •. S (6x − x³) dx 3 3 a. | (12x − 2x³) dx = | (੧) 0 0 (Simplify your answer.) b. S (6x-x³) dx = | (Simplify your answer.) 3

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